print(‘String does not contain substring’) The first argument is the string you are searching, and the second is the substring you are looking for. It also returns a Boolean. But these methods aren’t the only ones you can use to determine the existence of a substring in a string in ...
s = 'Does this string contain a substring?'print('\'string\' location -> {}'.format(s.find('string')))print('\'spring\' location -> {}'.format(s.find('spring'))) 'string' location -> 10'spring' location -> -1 默认情况...
However, there’s a better way to identify which cells in a column contain a substring: you’ll usepandas! In this example, you’ll work with a CSV file that contains fake company names and slogans. You can download the file below if you want to work along: ...
original_string = "Hello, world!" substring = "world" # 使用find()方法判断 if original_string.find(substring) != -1: print(f"The original string contains the substring '{substring}'.") else: print(f"The original string does not contain the substring '{substring}'.") 3. 判断原始字符...
string="Hello, world!"substrings=["Hello","world"]forsubstringinsubstrings:ifstring.count(substring)>0:print(f"The string '{string}' contains the substring '{substring}'")else:print(f"The string '{string}' does not contain the substring '{substring}'") ...
s='Does this string contain a substring?'print('\'string\'location -> {}'.format(s.find('string')))print('\'spring\'location -> {}'.format(s.find('spring')))'string'location->10'spring'location->-1 find()默认情况下返回子字符串第一次出现的第一个字符的索引,并返回 -1如果未找到...
s='Does this string contain a substring?'print('\'string\' location -> {}'.format(s.find('string')))print('\'spring\' location -> {}'.format(s.find('spring'))) 代码语言:javascript 代码运行次数:0 运行 AI代码解释 'string'location->10'spring'location->-1 ...
print("The string does not contain 'CA'") In this example, theinoperator checks if the substring"CA"is present in thestatestring variable, which represents a U.S. state name. The code will output “The string contains ‘CA'” since “California” includes “CA”. Theinoperator is case...
s = 'Does this string contain a substring?'print('\'string\' location -> {}'.format(s.find('string')))print('\'spring\' location -> {}'.format(s.find('spring'))) 1. 'string' location -> 10'spring' location -> -1
s = 'Does this string contain a substring?'print('\'string\' location -> {}'.format(s.find('string')))print('\'spring\' location -> {}'.format(s.find('spring')))'string' location -> 10'spring' location -> -1 默认情况下,find()返回子字符串第一次出现的第一个字符的索引,如果...