index = pinecone.Index("example-index")index.upsert([ ("A", [0.1, 0.1, 0.1, 0.1], {"genre": "comedy", "year": 2020}),)index.query( vector=[0.1, 0.1, 0.1, 0.1], filter={ "genre": {"$eq": "documentary"}, "year"
## $ Crime : int 0 0 0 0 0 1 0 0 0 0 ... ## $ Documentary: int 0 0 0 0 0 0 0 0 0 0 ... ## $ Drama : int 0 0 0 1 0 0 0 0 0 0 ... ## $ Fantasy : int 0 1 0 0 0 0 0 0 0 0 ... ## $ Noir : int 0 0 0 0 0 0 0 0 0 0 ... ## $ ...
documentary = "难以置信的事实" 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 这些例子可以帮助你更好地理解如何给变量取名字,特别是在不同的情况下,你可以使用不同的命名方式。当然,如果你有其他的需求,也可以根据自己的需求来取名字。 好的,上面讲了Python中...
[ "Action", "Adventure", "Animation", "Children", "Comedy", "Fantasy", "IMAX", "Romance", "Sci-Fi", "Western", "Crime", "Mystery", "Drama", "Horror", "Thriller", "Film-Noir", "War", "Musical", "Documentary" ] # 初始化变量 df = pd.DataFrame(columns=["Title", "Popularity...
radio( "What's your favorite movie genre", [":rainbow[Comedy]", "***Drama***", "Documentary :movie_camera:"], index=None, ) st.write("You selected:", genre) 这段代码使用了Streamlit库来创建一个简单的交互式应用程序。首先,它导入了Streamlit库。然后,它使用`st.radio`函数创建了一个单选...
unique(all_genres) print(genres) ['Animation' "Children's" 'Comedy' 'Adventure' 'Fantasy' 'Romance' 'Drama' 'Action' 'Crime' 'Thriller' 'Horror' 'Sci-Fi' 'Documentary' 'War' 'Musical' 'Mystery' 'Film-Noir' 'Western'] zero_matrix = np.zeros((len(movies), len(genres))) dummies ...
filter={"genre": {"$eq":"documentary"},"year":2019}, 它确实将结果过滤到“流派”和“年份”附近的向量。您还可以按概念或主题过滤矢量。 现在的挑战是,在企业环境中,它包括其他业务过滤器。解决来自数据源的数据缺乏建模的问题非常重要(想想表结构和元数据)。通过减少与结构化数据相矛盾的错误表达式来提高...
Documentary 127 War 143 Crime 211 Children's 251 Sci-Fi 276 Adventure 283 Horror 343 Romance 471 Thriller 492 Action 503 Comedy 1200 Drama 1603 导入用户数据,同时检查用户数据 #用户数量:总数、按性别、年龄、职业统计 import pandas as pd; import re import numpy as np #sep:分隔符,names:列名,occ...
st.markdown('- 按钮')ifst.button('Say hello'):st.write('Why hello there')st.markdown('- 单选框')genre=st.radio("选择你喜欢的?",('Comedy','Drama','Documentary'))st.write('你选择了:',genre)st.markdown('- 复选框')agree=st.checkbox('I agree')ifagree:st.write('感谢你同意了'...
radio( "What's your favorite movie genre", ('Comedy', 'Drama', 'Documentary')) if genre == 'Comedy': st.write('You selected comedy.') else: st.write("You didn't select comedy.") 相关用法 Python Streamlit st.experimental_singleton.clear用法及代码示例 Python Streamlit st.bokeh_chart...