Out[75]: 0.5 方法二:import未来支持的语言特征division(精确除法) Python的'/'除法默认使用截断除(Truncating Division),导入division模块后,Python才会默认使用精确除法。当导入了精确除后,若想再使用截断除,可以使用取整除'//',同时也被成为地板除。 In [92]: %%file testFloat.py from __future__ import d...
bit operators. Arithmetic operators, python arithmetic operators add exponents (**) and divisor (//) on the basis of addition (+) minus (-) multiplied by (*) divided by (/) remainder (%). Add, subtract, multiply and divide without further ado. The remainder is the remaining value after...
如要使用 floor 除法 并且得到整数结果(丢掉任何小数部分),你可以使用 // 运算符;要计算余数你可以使用 % >>> 17 / 3 # classic division returns a float 5.666666666666667 >>> >>> 17 // 3 # floor division discards the fractional part 5 >>> 17 % 3 # the % operator returns the remainder o...
# subtraction (-) operator print(a-b) # multiplication (*) operator print(a*b) # division (/) operator print(b/a) # modulus (%) operator print(a%b) # prints the remainder of a/b # exponent (**) operator print(a**b) #prints a^b 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. ...
>>> 17 % 3 # the % operator returns the remainder of the division除法只取余数 2 >>> 5 * 3 + 2 # result * divisor + remainder 加法乘法混合运算 17 With Python, it is possible to use the ** operator to calculate powers [1]:用python进行次方运算即运算幂 >>> 5 ** 2 # 5 ...
print "// operator", a//b, b//a 1. 5.12 模运算 remainder函数逐个返回两个数组中元素相除后的余数。如果第二个数字为0,则直接返回0。 a = np.arange(-4, 4) print "Remainder", np.remainder(a, 2) #等同于a % 2 #output Remainder [0 1 0 1 0 1 0 1] ...
import operator operator.mod(3 , 4) #输出 3 operator.mod(10 , 2) #输出 0 operator.mod(6 , 4) #输出 2 当然, 你也可以用负数 : -9 % 7 #输出 5 9 % -7 #输出 -5 -9 % -7 #输出 -2 如果需要找到整数除法和模数的结果,可以使用divmod函数: quotient, remainder = divmod(9, 4) ...
In this condition, the modulo operator returns the remainder of dividing number by 2, and the equality operator compares the result with 0, returning True or False as the comparison’s result. Then you use the all() function to determine if all the conditions are true. In this example, ...
Division (/) always returns a float. To do floor division and get an integer result (discarding any fractional result) you can use the // operator; to calculate the remainder you can use %: >>> 17 / 3 # classic division returns a float ...
The//operator in Python 3 is used to perform floor-based division. This means thata // bfirst divides a by b and gets the integer quotient, while discarding the remainder. This means that the result ofa//bis always an integer.