方法二:使用列表推导式 list1=[1,2,3,4,5]list2=[3,4,5,6,7]# 保持顺序找到在list1中而不在list2中的元素difference1=[xforxinlist1ifxnotinlist2]# 保持顺序找到在list2中而不在list1中的元素difference2=[xforxinlist2ifxnotinlist1]# 输出差异值print("List1中不在List2中的元素:",difference...
在B中但不在A中 retD = list(set(listB).difference(set(listA))) print "retD is: ",retD retE = [i for i in listB if i not in listA] print "retE is: ",retE def main(): listA = [1,2,3,4,5] listB = [3,4,5,6,7] diff(listA,listB) if __name__ == '__main__...
thistuple=("apple","banana","cherry")print(thistuple[1]) 是否存在指定项,请使用in关键字 要确定列表中是否存在指定项,请使用in关键字 代码语言:javascript 代码运行次数:0 运行 AI代码解释 thislist=["apple","banana","cherry"]if"apple"inthislist:print("Yes, 'apple' is in the fruits list") ...
importcollections Sale=collections.namedtuple('Sale','productid customerid data quantity price')sales=list()sales.append(Sale(432,921,"2018-04-01",3,8.2))sales.append(Sale(543,879,"2018-03-31",6,8.1))print(sales)[out][Sale(productid=432,customerid=921,data='2018-04-01',quantity=3,pr...
1. 获取两个list 的交集 print list(set(a).intersection(set(b))) 2. 获取两个list 的并集 print list(set(a).union(set(b))) 3. 获取两个 list 的差集 print list(set(b).difference(set(a))) # b中有而a中没有的 AI检测代码解析 ...
Python 取list 差集 python set取差集 交集(intersection) example: valid = set(['yellow', 'red', 'blue', 'green', 'black']) input_set = set(['red', 'brown']) print(input_set.intersection(valid)) ### 输出:set(['red']) # 方法一:...
difference_update() set1.difference_update(set2) 从set1 中删除与 set2 相同的元素 discard() set1.discard(elem) 删除set1 中的 elem 元素 intersection() set3 = set1.intersection(set2) 取set1 和 set2 的交集给 set3 intersection_update() set1.intersection_update(set2) 取set1和 set2 的交...
That also means that you can't delete an element or sort atuple. However, you could add new element to both list and tuple with the onlydifference that you will change id of the tuple by adding element(tuple是不可更改的数据类型,这也意味着你不能去删除tuple中的元素或者是对tuple进行排序,...
A=set('hello')B=set('world')A.union(B)# 并集,输出:{'d', 'e', 'h', 'l', 'o', 'r', 'w'}A.intersection(B)# 交集,输出:{'l', 'o'}A.difference(B)# 差集,输出:{'d', 'r', 'w'} 2、eval() 之前有人问如何用python写一个四则运算器,输入字符串公式,直接产生结果。
#Operations on setmy_set = {1, 2, 3, 4}my_set_2 = {3, 4, 5, 6}print(my_set.union(my_set_2))print(my_set.intersection(my_set_2))print(my_set.difference(my_set_2))print(my_set.symmetric_difference(my_set_2))my_set.clear()print(my_set)Output:{1, 2, 3, 4, 5, 6}...