解法二，想通过交换key、value的值来获取key:new_scores={v:kfork,vinscores.items()}keys=new_score...
def get_key_by_value(dictionary, value): keys = [] for key, val in dictionary.items(): if val == value: keys.append(key) return keys # 示例字典 my_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 2} # 查找值为2的键 value_to_find = 2 keys = get_key_by_value(my_dict, ...
'orange':3}# 指定要查找的valuevalue_to_find=2# 遍历字典中的键值对forkey,valueinmy_dict.items...
keys = ['a', 'b', 'c'] default_value = 0 my_dict = pd.Series(default_value, index=keys).to_dict() print(my_dict) # 输出: {'a': 0, 'b': 0, 'c': 0} 在上面的示例中,首先创建了一个pandas.Series对象,然后使用.to_dict()方法将其转换为字典。 总结 在Python 中,有多种方法可...
def get_keys_by_value(dictionary, value): keys = [] for key, val in dictionary.items(): if val == value: keys.append(key) return keys my_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 2} value = 2 keys = get_keys_by_value(my_dict, value) print(keys) # 输出 ['b', ...
defconvert_value_to_bool(dictionary,key):ifkeyindictionary:ifdictionary[key].lower()=="true":dictionary[key]=Trueelifdictionary[key].lower()=="false":dictionary[key]=Falseelse:return"Error: Cannot convert value to boolean"returndictionaryelse:return"Error:Keynotfound ...
my_dict={"apple":1,"banana":2,"orange":3,"grape":4}defget_key_by_value(dictionary,value):forkey,valindictionary.items():ifval==value:returnkeyreturnNonevalue_to_find=3result=get_key_by_value(my_dict,value_to_find)print(f"The key for value{value_to_find}is:{result}") ...
引用一段Python3文档里面的原话。 If keys,values and items views are iterated overwithno intervening modifications to the dictionary,the order of items will directly correspond. 也就是说,在你迭代的过程中如果没有发生对字典的修改,那么.keys() and .values 这两个函数返回的 dict-view对象总是保持对应...
这种情况可以先使用字典推导式反转原字典的key和value,然后就可以根据value选key了。对于Python3: dicxx = {'a':'001', 'b':'002'} new_dict = {v:k for k,v in dicxx.items()} # {'001': 'a', '002': 'b'} new_dict['001'] # 'a' 有用4 回复 ifthisthenthat: 这个只适合value是...
Dict['Value_set'] = 2, 3, 4 print("\nDictionary after adding 3 elements: ") print(Dict) # Updating existing Key's Value Dict[2] = 'Welcome' print("\nUpdated key value: ") print(Dict) # Adding Nested Key value to Dictionary ...