AI代码解释 Seconds since epoch:1565070251.7134922———-Current date and time:Tue Aug611:14:112019———-Local time:time.struct_time(tm_year=2019,tm_mon=8,tm_mday=6,tm_hour=11,tm_min=14,tm_sec=11,tm_wday=1,tm_yday=
通常的 f - 字符串格式说明符 允许更细致地控制所要显示的表达式结果: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 >>>delta=date.today()-member_since>>>f{user=!s}{delta.days=:,d}user=eric_idle delta.days=16,075 = 说明符将输出整个表达式,以便详细演示计算过程: 代码语言:javascript 代码...
last_month = today.replace(day=1) - timedelta(days=1) print("上个月的最后一天是:", last_month) 计算本月的天数 import calendar days_in_month = calendar.monthrange(today.year, today.month)[1] print("本月有", days_in_month, "天") 判断两个日期是否是同一个月 date1 = date(2023, 4...
#date.fromtimestampprint("Converting secondstodateandtime:n")print(datetime.date.fromtimestamp(23456789),end='n---n') #timedeltab1=datetime.timedelta(days=30, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=4, weeks=8)b2=datetime.timedelta(days=3, seconds=0, microseconds=0, m...
#date.fromtimestamp print("Converting seconds to date and time:n") print(datetime.date.fromtimestamp(23456789),end='n---n') #timedelta b1=datetime.timedelta(days=30, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=4, weeks=8) b2=datetime...
1fromdatetimeimportdate2fromdatetimeimportdatetime3fromdatetimeimporttimedelta45#计算两个日期相差多少天6d1 = date(2018, 10, 18);7d2 = date(2017, 12, 31);89print("(2018, 10, 18)与(2017, 12, 31)相差:", (d1 - d2).days,"天!");1011#获取两个日期时间的时间差12time1 = datetime(2019...
datetime.date(year, month, day) The date object constructor takes three integer arguments and should be within the specified range: MINYEAR <= year <= MAXYEAR 1 <= month <= 12 1 <= day <= number of days in the given month and year In the code above, MINYEAR is 1 and MAXYEAR ...
utc_date=datetime.utcfromtimestamp(seconds_since_epoch) print(utc_date) Output: 2019-11-01 09:53:20.657171 Simple date arithmetic: import datetime today = datetime.date.today() print('Today:', today) yesterday = today - datetime.timedelta(days=1) ...
from dateutil.relativedelta import relativedeltadef _add_new_data(ts, dat, type='day'): if type == 'day': new_index = ts.index[-1] + relativedelta(days=1) elif type == 'month': new_index = ts.index[-1] + relativedelta(months=1) ts[new_index] = datdef add_today_data(model,...
units Out[23]: u'days since 0000-01-01 00:00:00' When code attempted to translate the time data into datetime objects I would get the following error: File "netcdf_year_value_error.py", line 10, in <module> t_yrs = ncf.num2date(time[:], units=time.units, calendar=time....