from datetime import datetime, timedelta # 获取当前时间 now = datetime.now() print("当前时间:", now) # 创建一个 timedelta 对象 time_to_subtract = timedelta(days=1, hours=2, minutes=3, seconds=4) # 从当前时间减去 timedelta 对象 new_time = now - time_to_subtract print("减去1天2小时...
在Python中,我们可以使用timedelta类来进行时间的加减运算。timedelta类接受一个关键字参数minutes,用于指定需要减少的分钟数。 minutes_to_subtract=15time_obj-=datetime.timedelta(minutes=minutes_to_subtract) 1. 2. 上面的代码中,我们将需要减少的分钟数15传递给timedelta类的minutes参数,并使用减法操作符-=来减少...
Python的datetime可以处理2种类型的时间,分别为offset-naive和offset-aware。前者是指没有包含时区信息的时间,后者是指包含时区信息的时间,只有同类型的时间才能进行减法运算和比较。datetime模块的函数在默认情况下都只生成offset-naive类型的datetime对象,例如now()、utcnow()、fromtimestamp()、utcfromtimestamp()和...
years, months, weeks, days, hours, minutes, seconds, microseconds:相对值,可能是负数,加上(add)或减去(subtract)相对值,使用relativedelta中的相对值对原始的datetime进行相应的算术运算。 year, month, day, hour, minute, second, microsecond:绝对值,加上(add)或减去(subtract)一个绝对值,不是对原始的date...
importdatetimeimportcalendar future=datetime.datetime.utcnow()+datetime.timedelta(minutes=5)print(calendar.timegm(future.timetuple())) Output: 1621069619 10在 Python 中遍历一系列日期 importdatetime start=datetime.datetime.strptime("21-06-2020","%d-%m-%Y")end=datetime.datetime.strptime("05-07-2020"...
# 设置时间间隔为2小时time_delta_add=datetime.timedelta(hours=2)# 进行时间加法new_time_add=current_time+time_delta_addprint("增加2小时后的时间:",new_time_add)# 设置时间间隔为30分钟time_delta_subtract=datetime.timedelta(minutes=30)# 进行时间减法new_time_subtract=current_time-time_delta_subtract...
sub_mins =datetime.today() + relativedelta(minutes=-6) sub_seconds =datetime.today() + relativedelta(seconds=-6) print("Current Date Time:",datetime.today()) print("Subtract 6 days:", add_days) print("Subtract 6 months:", add_months) ...
dt1 = pendulum.datetime(2021, 10, 3) print(dt2.timezone.name) # UTC dt2 = pendulum.datetime(2021, 10, 3, tz="Asia/Shanghai") print(dt2.timezone.name) # Asia/Shanghai 不指定,就是默认的 UTC 0 时区 创建时间对象时可以指定时区,例如我们的时区名称是Asia/Shanghai ...
timezone switching>>> now_in_paris.in_timezone('UTC')'2016-07-03T22:49:58.502116+00:00'>>> tomorrow = pendulum.now().add(days=1)>>> last_week = pendulum.now().subtract(weeks=1)>>> past = pendulum.now().subtract(minutes=2)>>> past.diff_for_humans()>>> '2 minutes ago'>...
For instance, you might want to add three days and subtract four hours: Python >>> delta = timedelta(days=+3, hours=-4) >>> now + delta datetime.datetime(2020, 1, 29, 5, 37, 46, 380905) In this example, you add three days and subtract four hours, so the new datetime is ...