前面讲到了,我们可以使用变量来指定不同的数据类型,对网工来说,常用的数据类型的有字符串(String), 整数(Integer), 列表(List), 字典(Dictionary),浮点数(Float),布尔(Boolean)。另外不是很常用的但需要了解的数据类型还包括集合(set), 元组(tuple)以及空值(None),下面一一举例讲解。
import datetime from random import choice from time import time from openpyxl import load_workbook from openpyxl.utils import get_column_letter# 设置文件 mingcaddr = "openpyxl.xlsx"# 打开文件wb = load_workbook(addr)# 创建一张新表ws = wb.create_sheet()# 第一行输入ws.append(['TIME', 'TITL...
字符串(str)、元组(tuple)等类型,这一点跟集合类型对元素的要求是一样的;很显然,之前我们讲的列表(list)和集合(set)不能作为字典中的键,字典类型本身也不能再作为字典中的键,因为字典也是可变类型,但是列表、集合、字典都可以作为字典中的值,例如:
class CreateUserRequest(BaseModel): username: str = Field(..., min_length=4, description="Username must be at least 4 characters long.") email: str = Field(..., regex=r".+@\w+\.\w+", description="Valid email format required.") bio: Optional[str] = Field(None, max_length=256,...
The 'tuple1' contains the elements: 123, 'xyz', 'zara' and the 'tuple2' contains the elements: 456, 'abc'. Then the length of the tuples are retrieved using the len() method.Open Compiler tuple1, tuple2 = (123, 'xyz', 'zara'), (456, 'abc') print ("First tuple length : ...
和时间复杂度相比不那么重要,一般算法采取的措施为用空间换时间,即用一部分的空间消耗来缩短计算时间。 递归 汉诺塔问题(递归调用) # 汉诺塔算法defHanNoTa(n, a, b, c):ifn >0:HanNoTa(n -1, a, c, b)print(f"moving form{a}to{c}")HanNoTa(n -1, b, a, c)HanNoTa(3,"A","B","C")...
(tuple): '''A mock base class for named tuples.''' __slots__ = () _fields = () def __new__(cls, *args, **kwargs): 'Create a new instance of the named tuple.' return tuple.__new__(cls, *args) @classmethod def _make(cls, iterable, new=tuple....
()def Create(name, length):reset()Skip(-length * 0.1)begin_poly()forward(length * 1.1)end_poly()handForm = get_poly()register_shape(name, handForm)def Write(msg,obj=None):if obj=='Watch':Watch.write(msg, align="center", font=("Courier", 14, "bold"))else:write(msg, align="...
ba2base(n, bitarray, /, group=0, sep=' ') -> strReturn a string containing the base n ASCII representation of the bitarray. Allowed values for n are 2, 4, 8, 16, 32 and 64. The bitarray has to be multiple of length 1, 2, 3, 4, 5 or 6 respectively. For n=32 the ...
Get the sound playback position of channelch(0-3) as a tuple of(sound_no, note_no). ReturnNonewhen playback has stopped. Math ceil(x) Return the smallest integer that is greater than or equal tox. floor(x) Return the largest integer that is less than or equal tox. ...