defcount_spaces(string):count=0forcharinstring:ifchar.isspace():count+=1returncount string="Hello world!"spaces=count_spaces(string)print("There are",spaces,"spaces in the string.") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 输出结果: There are 1 spaces in the string. 1. 3.2 将字符串...
Thestrip()method is useful when dealing with user input as it gets rid of surrounding spaces in the string. This means it doesn’t just remove spaces, it also removes tabs and new line characters, which are all characters we don’t usually want in user-provided strings. There are two mo...
count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start:end]. Optional arguments start and end are interpreted as in slice notation. """ return 0 def decode(self, encoding=None, errors=None): """ 解码 """ """ S....
Apython stringis a list of characters in an order. A character is anything you can type on the keyboard in one keystroke, like a letter, a number, or a backslash. Strings can also have spaces, tabs, and newline characters. For instance, given below is a string in Python. myStr="hel...
1.>>> str='stRINg lEArn' 2.>>> 3.>>> str.center(20) #生成20个字符长度,str排中间 4.' stRINg lEArn ' 5.>>> 6.>>> str.ljust(20) #str左对齐 7.'stRINg lEArn ' 8.>>> 9.>>> str.rjust(20) #str右对齐 10.' stRINg lEArn' ...
337 338 """ 339 return s.rindex(*args) 340 341 # Count non-overlapping occurrences of substring 342 def count(s, *args): 343 """count(s, sub[, start[,end]]) -> int 344 345 Return the number of occurrences of substring sub in string 346 s[start:end]. Optional arguments start ...
in a string of length width. Padding is 23 done using the specified fill character (default is a space) 24 """ 25 return "" 26 27 def count(self, sub, start=None, end=None): # real signature unknown; restored from __doc__ 28 """ 29 S.count(sub[, start[, end]]) -> int...
Mike has 5 apples.' substr = 'apples' # Occurrences of substring 'apples' in the string result = str1.count(substr) print("Number of substring occurrences:", result) # Occurrences of substring 'apples' from index 0 to index 40 start, end = 0, 40 result2 = str1.count(substr, start...
8.TabError: inconsistent use of tabs and spaces in indentation 缩进同时使用了空格和Tab。Tab和空格是不同的键,互相不等同。 s = 0 for i in range(1 , 6): s = s + i print( s) # 此处使用了Tab,看上去和上一行都是对齐的。 如何修改:缩进时,统一使用空格或者Tab,不要交替使用。
""" pass def count(self, sub, start=None, end=None): # real signature unknown; restored from __doc__ """ S.count(sub[, start[, end]]) -> int .count(sub[, start[, end]]返回子字符串sub in不重叠出现的次数 字符串(开始:结束)。可选参数start和end是用切片表示法解释。 """ return...