a nice string representation of the object. | If the argument is a string, the return value is the same object. | | Method resolution order: | str | basestring | object | | Methods defined here: | | __add__(...) | x.__add__(y) <==> x+y | | __contains__(...) | x...
>>> str.count('a') #字符串中匹配的次数 0 >>> str.count('n') #同上 2 >>> str.replace('EAR','ear') #匹配替换 'string learn' >>> str.replace('n','N') 'striNg lEARN' >>> str.replace('n','N',1) 'striNg lEARn' >>> str.strip('n') #删除字符串首尾匹配的字符,通常...
S.count(sub[, start[, end]]) -> int #判断子串在字符串中出现的次数 Return the number of non-overlapping occurrences of substring sub in string S[start:end]. Optional arguments start and end are interpreted as in slice notation. >>>str1="hello world">>>str1.count("l")3>>>str2="...
given, only the first count occurrences are replaced. """ return "" def rjust(self, width, fillchar=None): """ S.rjust(width[, fillchar]) -> str Return S right-justified in a string of length width. Padding is done using the specified fill character (default is a space). ""...
"""内容居中,width:总长度,fillchar:空白处填充内容,默认无""" 示例: a = "chl" print(a.center(9, "*")) 结果: ***chl*** 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. str.count(sub[, start[, end]]) Return the number of non-overlapping occurrences of substring sub in the range [st...
Return centered in a string of length width. Padding is done using the specified fillchar (default is a space). Changed in version 2.4: Support for the fillchar argument. str.count(sub[, start[, end]]) 返回sub子串的数量 Return the number of non-overlapping occurrences of substring sub in...
Return a copy of S with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced. >>> word = "this is a test" >>> word.replace("is", "eez") 'theez eez a test' ...
Write a Python program to get a string from a given string where all occurrences of its first char have been changed to '$', except the first char itself. Sample String : 'restart' Expected Result : 'resta$t' Click me to see the sample solution ...
space) """ return "" def count(self, sub, start=None, end=None): # real signature unknown; restored from __doc__ """ 从一个范围内的统计某str出现次数 S.count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start:end]....
S.count(sub[,start[,end]])->int Returnthenumberofnon-overlappingoccurrencesofsubstringsubin stringS[start:end].Optionalargumentsstartandendare interpretedasinslicenotation. (返回的数量重叠出现的子串子字符串(开始:结束)。可选参数的开始和结束解释为片符号。) ...