We can also count the number of dictionary keys using the “dict.keys()” function along with the “len()” function. Here is an example of how we can do that in a program: Code: (Printing the Number of Dictionary Keys) dict_value = {'Name' : 'Lily', 'Age': 22, 'Height': 5...
dict[key]返回key对应的值value dict.get(key,default)--返回字典中key对应的值,若未找到key,则返回default值,default值可不写 删除字典中的一项 del dict[key] 字典的遍历 遍历字典的键key for key in dict.keys():print(key) 遍历字典的值value for value in dict.values():print(value) 遍历字典的项 ...
'hello',1997,2000)After deleting tup:---NameErrorTraceback(most recent call last)<ipython-input-1-a12bbf13863f>in<module>()4del tup5print("After deleting tup : ")--->6print(tup)NameError:name'tup'is not defined 1.1.6 无关闭分隔符 当元组出现在二进制操作...
# 创建一个字典my_dict={"apple":2,"banana":3,"orange":5,"kiwi":1,"mango":5}# 设置要统计的值value_to_count=5# 初始化计数器count=0# 使用循环遍历统计值出现的次数forvalueinmy_dict.values():ifvalue==value_to_count:count+=1# 打印结果print("值",value_to_count,"出现的次数为:",coun...
1#使用__metaclass__(元类)的高级python用法2classSingleton2(type):3def__init__(cls,name,bases,dict):4super(Singleton2,cls).__init__(name,bases,dict)5cls._instance=None6def__call__(cls,*args,**kw):7ifcls._instance is None:8cls._instance=super(Singleton2,cls).__call__(*args,*...
keys = ['name', 'age', 'city']values = ['Xiuxiu', 16, 'Wuhan']my_dict = {key: value for key, value inzip(keys, values)} # 打印字典内容 print("字典内容：", my_dict)在这个示例中，我们首先定义两个列表 keys 和 values，它们包含了相同数量的元素。然后，我们使用列表推导式来创建字典...
dict.fromkeys(seq[, value]) seq -- 字典键值列表。 value -- 可选参数, 设置键序列(seq)的值。 (5)遍历key列表,利用count函数统计单词出现次数 2.代码实现 # 统计单词出现次数并把结果输出成字典# 数据输入str="Hello world, There are some test words. Hello world, There are some test words. Haha...
keys()、values()和items()方法,返回的类型是元组。 my_dict = {'a': 1, 'b': 2, 'c': 3} # 方式一:直接遍历字典 for key in my_dict: print(key, my_dict[key]) # 方式二:使用 items() 方法 for key, value in my_dict.items(): print(key, value) 3、字典in和not in 检查字典中...
del dict[key] 字典的遍历 遍历字典的键key for key in dict.keys():print(key) 遍历字典的值value for value in dict.values():print(value) 遍历字典的项 for item in dict.items():print(item) 是否一个键在字典中 注:值不能判断 in 或者 not in 删除字典项目 dict.clear()--删除字典中的所有...
a.语法一:字典[键],注意:键一定要存在,才能获取到对应的值 info_dict = {'name':'赵四','age':20,"gender":'male'} age = info_dict['age'] print(age) print(info_dict['hobby']) # KeyError 优化 if 'hobby' in info_dict: print(info_dict['hobby']) ...