To help you practice Python and interviewing skills, I selected three Python coding interview questions. Two are fromStrataScratch, and are the type of questions that require using Python to solve a specific bu
课程英文名:LeetCode In Python 50 Algorithms Coding Interview Questions 此视频教程共4.0小时,中英双语字幕,画质清晰无水印,源码附件全 下载地址 百度网盘地址:pan.baidu.com/s/1J9xysc 课程内容 LeetCode 本质上是一个 由最受欢迎的科技公司( 谷歌、亚马逊、Facebook、微软等)提出的真实 面试问题的巨大存储库 ...
https://www.hackerrank.com/interview/interview-preparation-kit LeetCode: https://leetcode.com/explore/interview/card/top-interview-questions-easy/ CodingBat : https://codingbat.com/python GeeksForGeeks: https://www.geeksforgeeks.org/p...
Leetcodeis an excellent resource with a ton of coding interview questions. Leetcodeallows you to submit your Python solutions to the coding questions and get instant feedback about the validity and the efficiency of your solutions. After you start working, you will learn a lot on the job and...
python(leetcode)-283 输出:说明:必须在原数组上操作,不能拷贝额外的数组。 尽量减少操作次数。 说下拿到这道题时的思路: 给人的感觉并不难,首先的想法就是遍历数组中每一个元素,判断如果为0则删除,同时末尾增加0 上代码(通过240ms)击败20%的用户
地址：http://www.pythontip.com/coding/code_oj3 python开发者社区地址：python开发者社区特点：分类全...
力扣(leetcode)-初级算法 轮转数组-做题思路与解法解析 示例一: 输入: nums = [1,2,3,4,5,6,7], k = 3 输出: [5,6,7,1,2,3,4] 解释: 向右轮转 1 步: [7,1,2,3,4,5,6] 向右轮转 2 步: [6,7,1,2,3,4,5] ...
Python3 reference for interview coding problems/light competitive programming. Contributions welcome! How I built this cheatsheet while teaching myself Python3 for various interviews and leetcoding for fun after not using Python for about a decade. This cheetsheet only contains code that I didn't ...
A collection of LeetCode questions to ace the coding interview! - Created using LeetHub v2 LeetCode Topics Database 0180-consecutive-numbers 0181-employees-earning-more-than-their-managers 0182-duplicate-emails 0184-department-highest-salary 0185-department-top-three-salaries 0196-delete-duplicate-email...
leetcode 56: 给出一个区间的集合,请合并所有重叠的区间。 输入: [[1,3],[2,6],[8,10],[15,18]] 输出: [[1,6],[8,10],[15,18]] 解释: 区间 [1,3] 和 [2,6] 重叠, 将它们合并为 [1,6].输入: [[1,4],[4,5]] 输出: [[1,5]] ...