Example 1: Input:5Output:TrueExplanation:1*1+2*2=5 Example 2: Input:3Output:False 翻译 中文题目链接 给定一个非负整数 c ,你要判断是否存在两个整数 a 和 b,使得 a*a + b*b = c。 示例1: 输入: 5输出: True解释: 1 * 1 + 2 * 2 = 5 示例2: 输入: 3输出: False 思路 双指针 a...
AI代码解释 classSolution:deftwoSum(self,nums,target):""":type nums:List[int]:type target:int:rtype:List[int]"""#用len()方法取得nums列表长度 n=len(nums)#x从0到n取值(不包括n)forxinrange(n):a=target-nums[x]#用in关键字查询nums列表中是否有aifainnums:#用index函数取得a的值在nums列表...
class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: # 初始化个位节点,先不做进位 newPoint = ListNode(l1.val + l2.val) # rt用来作为最后return的节点,tp用来遍历节点 rt, tp = newPoint, newPoint # l1,l2只要后面还有节点,就继续往后遍历;或者新链表还需要继续往后...
1classSolution:2"""3@param numbersbers : Give an array numbersbers of n integer4@return : Find all unique triplets in the array which gives the sum of zero.5"""6defSolution(self):7pass8defthreeSum(self, numbers):9#write your code here10numbers.sort()11ret =[]12n =len(numbers)13f...
给定nums=[2,7,11,15],target=9因为 nums[0]+nums[1]=2+7=9所以返回[0,1]来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/two-sum 英文题目 Question 1 Two Sum:Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may...
Python | Leetcode 之 Two Sum 恒仔 误入深度学习 5 人赞同了该文章 说来惭愧,到现在才开始刷Leetcode,但迟到总比不到好。 题目:Given an array of integers, return indices of the two numbers such that they add up to a specific target.You may assume that each input would have exactly one ...
从栈中分别弹出栈顶数字 adder1 和 adder2,计算 adder1 和 adder2 之和,再加上进位 carry,得到当前位置的和 sum。 如果sum >= 10 ,那么进位 carry = 1...
A binomial coefficient C(n, k) also gives the number of ways, disregarding order, that k objects can be chosen from among n objects; more formally, the number of k-element subsets (or k-combinations) of an n-element set. Given two numbers n and r, find value of nCr nCr = (n!)...
Write a Python program to calculate sum of digits of a number. Pictorial Presentation: Sample Solution: Python Code: # Prompt the user to input a four-digit number and convert it to an integer.num=int(input("Input a four-digit number: "))# Extract the thousands digit (x).x=num//1000...
For larger arrays of complex numbers, use NumPy’s complex data types For very performance-critical code, consider using Cython or Numba Here’s a performance comparison: import numpy as np import time # Pure Python def complex_operation_python(n): ...