def get_random_vowel(): vowels = 'aeiouAEIOU' return random.choice(vowels) random_vowel = get_random_vowel() print(random_vowel) 2、生成随机辅音字母 import random def get_random_consonant(): consonants = 'bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ' return random.choice(consonants) random_conson...
def search4vowels(): """Display any vowels found in an asked-for word""" vowels = set('aeiou') word = input('Provide a word to search for vowels: ') found = vowels.intersection(set(word)) for vowel in found: print(vowel) 加三重引号的字符串称为docstring,它们主要作为文档,用来描述一...
6、列表推导式 列表推导式是for循环的简易形式,可以在一行代码里创建一个新列表,同时能通过if语句进行判断筛选 代码语言:javascript 代码运行次数:0 运行 AI代码解释 defget_vowels(string):return[vowelforvowelinstringifvowelin'aeiou']print("Vowels are:",get_vowels('This is some random string')) 输出: ...
6、列表推导式 列表推导式是for循环的简易形式,可以在一行代码里创建一个新列表,同时能通过if语句进行判断筛选 def get_vowels(string): return [vowel for vowel in string if vowel in 'aeiou'] print("Vowels are:", get_vowels('This is some random string')) 1. 2. 3. 4. 输出: Vowels are: [...
for i in string: if i in my_vowels: print(f"Current vowel: {i}") print(f"Number of vowels found so far: {next(current_counter)}") 输出如下。 Current vowel: i Number of vowels found so far: 0 Current vowel: i Number of vowels found so far: 1 Current vowel: u Number of ...
您还可以利用sorted()以排序和反转的顺序遍历一个字符串:>>> for vowel in sorted(vowels, reverse=True): ... print(vowel) ... ... u o i e a sorted()的reverse参数允许你以降序排列可重复项,包括字符串。所以,如果你需要一个字符串的字符按照相反的字母顺序排序,那么sorted()就是为你准备的。Remov...
Python 整洁编程(全) 原文:Clean Python 协议:CC BY-NC-SA 4.0 一、Pythonic 式思维 Python 与其他语言的不同之处在于,它是一种简单而有深度的语言。因为简单,所以谨慎编写代码要重要得多,尤其是在大项目中,因为代码很容易变得复杂臃肿。Python 有一
得到状态转移方程dp[i] += dp[i-1] 代码 class Solution: def countVowelStrings(self, n: int) -> int: dp = [1,1,1,1,1] for _ in range(n-1): for i in range(1,5): dp[i] += dp[i-1] return sum(dp)
for word in words: vowels = len(patt_vowel.findall(word)) if vowels: ratio = 1. * (len(word) - vowels) / vowels ratiosdict.setdefault(ratio, set()).add(word) else: onlyconsonant.append(word) return (onlyconsonant, list(sorted(ratiosdict.items(), reverse=True)[0]))if __name_...
for vowel in vowels: if vowel not in word: return False return True word=input("Enter a word:") if isVowelWord(word): print(word,"contains every vowel") else: print(word,"does not contain every vowel") 1. 2. 3. 4. 5.