1classSolution:2#@param s, a string3#@return a boolean4defisPalindrome(self, s):5ret =False6s =s.lower()7ss =""8foriins:9ifi.isalnum():10ss +=i11h =012e = len(ss)-113while(h<e):14if(ss[h] ==ss[e]):15h += 116e -= 117else:18break19ifh>=e:20ret =True21return...
下面是判断回文数的流程图: YesNoStartIs input a palindrome?Output: TrueOutput: FalseEnd 类图 下面是一个简单的Python类,用于判断一个字符串是否为回文: Palindrome- string s+is_palindrome() 在这个类中,我们定义了一个字符串变量s,并且有一个方法is_palindrome用于判断s是否为回文。 结语 通过本文的介绍,...
my_string = "abcba"if my_string == my_string[::-1]:print("palindrome")else: print("not palindrome")# Output# palindrome 1. 统计列表元素的个数 有多种方式可以实现这个技巧,但我最喜欢的是采用 Counter 类。 Counter 可以统计给定列表中每个元素的个数,返回一个字典格式。示例如下,其中 most_common...
代码 classSolution(object):defisPalindrome(self, s):""" :type s: str :rtype: bool """ss = []# 这里若用string也可以,但是大数据会TLEforcharins.lower():ifchar.isalnum(): ss.append(char)returnss == ss[::-1] 双指针 classSolution:# @param s, a string# @return a booleandefisPalin...
For the purpose of this problem, we define empty string as valid palindrome. 解题思路1:利用python的list comprehension 以及string 的 isalnum()函数我们可以写出极为简短的解决方法 (原创): classSolution:#@param s, a string#@return a booleandefisPalindrome(self, s): ...
my_string = "abcba" if my_string == my_string[::-1]: print("palindrome") else: ...
# palindrome string # iterative method # function def isPalindrome(string): for i in range(int(len(string)/2)): if string[i] != string[len(string)-i-1]: return "No" return "Yes" s1="tenet" s2="defined" print(s1,":",isPalindrome(s1)) print(s2,":",isPalindrome(s2)...
string convert(string s, int numRows); 示例1: 输入:s = "PAYPALISHIRING", numRows = 3 输出:"PAHNAPLSIIGYIR" 示例2: 输入:s = "PAYPALISHIRING", numRows = 4 输出:"PINALSIGYAHRPI" 示例3: 输入:s = "A", numRows = 1 输出:"A" ...
Here is source code of the Python Program to check whether a string is a palindrome or not using recursion. The program output is also shown below. defis_palindrome(s):iflen(s)<1:returnTrueelse:ifs[0]==s[-1]:returnis_palindrome(s[1:-1])else:returnFalsea=str(input("Enter string:...
Program for Palindrome number in Python A palindrome number is a number or a string that when reversed, remains unaltered. num = int(input("Enter a number")) temp = num rvrs = 0 while(num>0): dig = num%10 rvrs = rvrs*10+dig num = num//10 if(temp == rev): print("The number...