def is_palindrome(string): """判断传入字符串是否是回文串 """ left = 0 right = len(string) - 1 while left < right: if string[left] != string[right]: return False left += 1 right -= 1 return True # 计数 count = 0 # 枚举字符组合 for i in range(len(s)): for j in range(...
1classSolution:2#@param s, a string3#@return a boolean4defisPalindrome(self, s):5ret =False6s =s.lower()7ss =""8foriins:9ifi.isalnum():10ss +=i11h =012e = len(ss)-113while(h<e):14if(ss[h] ==ss[e]):15h += 116e -= 117else:18break19ifh>=e:20ret =True21return...
my_string = "abcba" m if my_string == my_string[::-1]: print("palindrome") else: print("not palindrome") # Output # palindrome 10. 列表的要素频率 有多种方式都可以完成这项任务,而我最喜欢用Python的Counter 类。Python计数器追踪每个要素的频率,Counter()反馈回一个字典,其中要素是键,频率是...
9. 检查给定字符串是否是回文(Palindrome) 反转字符串已经在上文中讨论过。因此,回文成为Python中一个简单的程序。 my_string = "abcba" m if my_string == my_string[::-1]: print("palindrome") else: print("not palindrome") # Output # palindrome 10. 列表的要素频率 有多种方式都可以完成这项任...
LeetCode Given a string which consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters. This is case sensitive, for example"Aa"is not considered a palindrome here. Note: ...
new_string = ''.join(temp_set) print(new_string) 3.反转字符串 这段代码是使用Python切片操作来反转字符串。 #使用切片反转字符串 my_string = "ABCDE" reversed_string = my_string [::-1] print(reversed_string) #output 4.将字符串列表组合成单个字符串 ...
题目地址:https://leetcode.com/problems/palindrome-partitioning/description/ 题目描述 Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: AI检测代码解析 ...
()# Constant to assume string is Palindrome is_palindrome=True # Get the user's choice.choice=int(input('\nEnter your choice: '))# Perform the selected action.ifchoice==Continue:line=input("\nEnter a string: ")str_lower=re.sub("[^a-z0-9]","",line.lower())foriinrange(0,len(...
is_palindrome('LOL') # returns true is_palindrome('ROTFL') # returns false is_pangram: Checks if the string is a pangram is_pangram('The quick brown fox jumps over the lazy dog') # returns true is_pangram('hello world') # returns false is_isogram: Checks if the string is an...
print(is_palindrome(123321)) print(is_palindrome(123231))16. 找出 100~999 之间的水仙花数一水仙花数所谓的水仙花数是指:一个n 位数(),它的每个位上的数字的n 次幂之和等于它本身。 例如153,370,371,407等都是水仙花数。就拿153来说,。for num in range(100, 1000): low = num % 10 mid = num...