) else: print("The string is not a palindrome.") Run Code Output The string is a palindrome. Note: To test the program, change the value of my_str in the program. In this program, we have taken a string stored in my_str. Using the method casefold() we make it suitable for ...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): rev_string = string[::-1] return string == rev_string # Main code x = "Google" if isPalindrome(x): print(x,"is a palindrome string") else: print(x,"is...
Here is source code of the Python Program to check whether a string is a palindrome or not using recursion. The program output is also shown below. def is_palindrome(s): if len(s) < 1: return True else: if s[0] == s[-1]: return is_palindrome(s[1:-1]) else: return False ...
NameError: name'area'isnotdefined area是函数中的局部变量,因此我们无法从函数外部访问它。 6.2. 有些函数返回 None 如果一个函数没有return语句,它会返回None,这是一个特殊的值,类似于True和False。例如,这里是第三章中的repeat函数。 defrepeat(word, n):print(word * n) 如果我们像这样调用它,它会显示...
Palindrome Partitioning 题目大意 将一个字符串分割成若干个子字符串,使得子字符串都是回文字符串,要求列出所有的分割方案。 解题思路 DFS 代码 class Solution(object): def partition(self, s): """ :type s: str :rtype: List[List[str]] """ ...
class Solution: def isPalindrome(self, head) -> bool: #链表为空,直接返回true if head is None: return True #找到链表的中点 middle_point = self.middle_point(head) second_start = self.reverse_list(middle_point.next) #判断前半部分和后半部分是否相等 result = True first = head second = se...
[LeetCode&Python] Problem 409. Longest Palindrome Given a string which consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters. This is case sensitive, for example"Aa"is not considered a palindrome here....
(Stacked Histogram for Continuous Variable) 22、类别变量堆积直方图(Stacked Histogram for Categorical Variable) 23、密度图(Density Plot) 24、带直方图的密度图(Density Curves with Histogram) 25、山峰叠峦图(Joy Plot) 26、分布点图(Distributed Dot Plot) 27、箱图(boxplot) 28、箱图结合点图(Dot + ...
if __name__ == '__main__': num = int(input('请输入正整数: ')) if is_palindrome(num) and is_prime(num): print('%d是回文素数' % num) 在屏幕上显示跑马灯文字 代码语言:javascript 代码运行次数:0 运行 AI代码解释 import os import time def main(): content = '北京欢迎你为你开天辟地...
deffun_A(x,y=3):returnx*y#转换后的lamdba表达式(注意参数)lambda x,y=3:x*y#利用filter()和lambda表达式快速求出100以内所有3的倍数list(filter(lambda n:not(n%3),range(1,100)))#能整除的时候返回1[3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,...