2,3],[4,5,6],[7,8,9]]transposed_matrix=transpose_matrix_zip(matrix)print(transposed_matrix)deftranspose_matrix_list_comprehension(matrix):return[[matrix[j][i]forjinrange(len(matrix
分享给大家供大家参考,具体如下:矩阵转置方法一 :使用常规的思路 def transpose(M):# 初始化转置后的矩阵 result = [] # 获取转置前的行和列 row, col = shape(M) # 先对列进行循环 for i in range(col): # 外层循环的容器 item = [] # 在列循环的内部进行行的循环 python 矩阵旋转 代码 ...
代码语言:javascript 复制 deftranspose1(matrix):cols=len(matrix[0])return[[row[i]forrowinmatrix]foriinrange(0,cols)]deftranspose2(matrix):transposed=[]foriinrange(len(matrix[0])):transposed.append([row[i]forrowinmatrix])returntransposed deftranspose3(matrix):transposed=[]foriinrange(len(matrix...
The transpose of a matrix is the matrix flipped over it's main diagonal, switching the row and column indices of the matrix. Example 1: Input:[[1,2,3],[4,5,6],[7,8,9]] Output:[[1,4,7],[2,5,8],[3,6,9]] Example 2: Input:[[1,2,3],[4,5,6]] Output:[[1,4],[...
System.out.println(transposematrix); transposematrix.clear(); } sc.close(); } }/* Code Running Result 请输入矩阵行列 2 3 1 2 3 4 5 6 原矩阵 [1, 2, 3] [4, 5, 6] 转置矩阵 [1, 4] [2, 5] [3, 6] */ 接下来就要提现 Python 的强大了 ...
importnumpyasnp# 创建一个3x2的矩阵matrix=np.array([[1,2],[3,4],[5,6]])# 对矩阵进行转置transposed_matrix=np.transpose(matrix)print(transposed_matrix) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 上面的代码中,我们首先使用NumPy库创建了一个3x2的矩阵,然后使用transpose()函数对矩阵进行了...
上述的三种方法受限于 Python解释器,效率不是非常高。 如果要进行专业的数值分析和计算的话,可以使用numpy库的matrix.transpose方法来翻转矩阵。 代码语言:javascript 复制 importnumpyasnp matrix=np.arange(9).reshape((3,3))assert matrix.transpose()==np.array([[0,3,6],[1,4,7],[2,5,8]])...
1. 使用numpy库的transpose函数 “`python import numpy as np matrix = np.array([[1, 2, 3], [4, 5, 6]]) # 转置矩阵 transposed_matrix = np.transpose(matrix) print(transposed_matrix) “` 2. 使用numpy库的T属性 “`python import numpy as np ...
Thezip(*matrix)trick is a Pythonic way to transpose a matrix by using thezipfunction along with unpacking (*) the matrix. 4. Using NumPy Library NumPy is a powerful library for numerical computing in Python. It provides a simple way to transpose a matrix using itsTattribute;there is also ...
{ for (int j = 0; j < cols; j++) { C[get_index(i, j, cols)] = A[get_index(i, j, cols)] - B[get_index(i, j, cols)]; } } } // 矩阵转置 void matrix_transpose(float* A, float* B, int rows, int cols) { for (int i = 0; i < rows; i++) { for (int j...