I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year") else: print("Not a leap year")...
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: return False else: return True while(True)...
days = function1(year, month, day) break elif month == 2: # 2月份 闰年29天 非闰年 28天 if isLeapYear(year): # 闰年 assert (1 <= day <= 29) # 在此范围 正确 可以计算 days = function1(year, month, day) break else: # 非闰年 assert 1 <= day <= 28 # 在此范围 正确 可以计...
not or and 逻辑运算符 = += -= *= /= %= //= **= &= | = ^= >>= <<= (复合)赋值运算符 5、练习 代码语言:javascript 代码运行次数:0 运行 AI代码解释 经典题目:输入年份判断闰年 year = int(input('请输入年份')) leap_year = year % 4 == 0 && year % 100 != 0 || year %...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
Years divisible by 100 are not leap years unless… Leap Year is divisible by 400 or 4 Now let’s look at the Python code that checks a year to see if it is a leap year. Here are a few steps to check: is 2024 a Leap Year? Step 1: Make sure the year can be divisible by 4 ...
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5. Leap Year ValidatorWrite a Python program that checks whether a given year is a leap year or not using boolean logic.Sample Solution:Code:def check_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) def main(): try: year = int(input("...
if int(year)% 100 != 0 and int(year) % 4 == 0: return True else: return False data = input("请输入年份:") if is_leap(data): print("是闰年") else: print("不是闰年") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11.
defis_leap(year):leap=Falseifyear%4==0:leap=Trueifyear%100==0:leap=Falseifyear%400==0:...