6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
#The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: return False else: return True while(True)...
Python- Leap Year Hi all, This does not bode too well but I have become stuck on the Leap YearPythonpractice test. Can you please let me know why the below code is not working? This one has got the better of me. year = int(input()) if year % 4 == 0: if year % 100 == ...
Example Code: importcalendar y=int(input("Enter a year: "))# [statement_on_True] if [condition] else [statement_on_false]print(y,"is a leap year")if(calendar.isleap(y))elseprint(y,"is not a leap year") The above code uses the conditional operator to display whether a year is a...
1.1 定义一个is_leap(year)函数,该函数可判断year是否为闰年。若是闰年,则返回True;否则返回False。 def is_leap(year): if int(year)% 100 != 0 and int(year) % 4 == 0: return True else: return False data = input("请输入年份:") ...
Python is known for its various built-in modules. Instead of writing the code for leap year manually using the conditions, we can simply use the Python module to check if the given year is a leap year or not as shown below: python ...
RUN 1: Enter the value of year: 2020 The given year is a leap year. RUN 2: Enter the value of year: 2021 The given year is a non-leap year. 2) Check leap year by simply checking the leap year conditionAs we know the condition to check the given year is a leap year or not....
"""输入年份,闰年输出True,平年输出FalseVersion: 1.0Author: 骆昊"""year=int(input('请输入年份: '))is_leap=year%4==0andyear%100!=0oryear%400==0print(f'{is_leap = }') 说明:对于格里历(Gregorian calendar),即今天我们使用的公历,判断闰年的规则是:1. 公元年份非4的倍数是平年;2. 公元年份为...
Write a Python program that checks whether a given year is a leap year or not using boolean logic.Sample Solution:Code:def check_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) def main(): try: year = int(input("Input a valid year: "...