The last method to check for a substring we used returned a Boolean value. This will work well in your code if all you need to know is if the substring simply exists in the string. But if you need to know the substring’s location in the string, you will need to use a different m...
Get Your Code:Click here to download the free sample codethat you’ll use to check if a string contains a substring. Take the Quiz:Test your knowledge with our interactive “How to Check if a Python String Contains a Substring” quiz. You’ll receive a score upon completion to help you...
To check if a Python string contains a substring, you can use theinoperator. It returnsTrueif the substring is found within the string, andFalseotherwise. For example,if "hello" in "hello world":will evaluate toTrue. Table of Contents Using the in Operator The simplest way to check if a...
StartCheck:起始位置大于等于0:起始位置小于0Substring:截取子串Substring
2. Usingfind()to check if a string contains another substring We can also usestring find() functionto check if string contains a substring or not. This function returns the first index position where substring is found, else returns -1. ...
A substring is the part of a string. Python string provides various methods to create a substring, check if it contains a substring, index of substring etc. …
The index method can’t return a number because the substring isn’t there, so we get a value error instead: In order to avoid thisTraceback Error, we can use the keywordinto check if a substring is contained in a string. In the case of Loops, it was used for iteration, whereas in...
ValueError: substring not found >>> str.index("n") #同find类似,返回第一次匹配的索引值 4 >>> str.rindex("n") #返回最后一次匹配的索引值 11 >>> str.count('a') #字符串中匹配的次数 0 >>> str.count('n') #同上 2 >>> str.replace('EAR','ear') #匹配替换 'string learn' >...
ascii_digits = string.digits# Output: 0123456789 forone_digitinascii_digits[:5]:# Loop through 01234 print(ord(one_digit)) Output: 48 49 50 51 52 在上面的代码片段中,我们遍历字符串 ABCDE 和 01234,并将每个字符转换为它们在 ASCII 表中的十进制表示。我们还可以使用 chr 函数执行反向操作,从而将...
Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure. s.find('peach',8)# 从index 7 开始往后找 ...