#🌾:capitalize() - 将字符串的第一个字符转换为大写string ="hello world"print("capitalize()示例:", string.capitalize())#输出:Hello world#🌾:casefold() - 将字符串转换为小写,并且移除大小写区别string ="Hello World"print("casefold()示例:", string.casefold())#输出:hello world#🌾:center()...
In order to avoid thisTraceback Error, we can use the keywordinto check if a substring is contained in a string. In the case of Loops, it was used for iteration, whereas in this case it’s a conditional that can be eithertrueorfalse.It’ll be true if the substring is part of the ...
337 338 """ 339 return s.rindex(*args) 340 341 # Count non-overlapping occurrences of substring 342 def count(s, *args): 343 """count(s, sub[, start[,end]]) -> int 344 345 Return the number of occurrences of substring sub in string 346 s[start:end]. Optional arguments start a...
main_string ="I learned English and Python with ZHouluobo. You can do it too!" # Index 0 print(main_string[0]) # Index 1 print(main_string[1]) # Check if Index 1 is whitespace print(main_string[1].isspace) # Slicing 1 print(main_string[0:11]) # Slicing 2: print(main_string...
Return a string which is the concatenation of the strings in the iterable. The separator between elements is S. li=['apple','peach','banana','peach','pear']# 形参为可迭代对象 1. sep=','# 指定逗号为连接符 sep.join(li)# 语法: 连接符.join(可迭代对象), 即将可迭代对象,有(分隔符)连...
rindex('o', 8)) # ValueError: substring not found 性质判断 可以通过字符串的startswith、endswith来判断字符串是否以某个字符串开头和结尾;还可以用is开头的方法判断字符串的特征,这些方法都返回布尔值,代码如下所示。 s1 = 'hello, world!' print(s1.startswith('He')) # False print(s1.startswith...
main_string = "I learned English and Python with ZHouluobo. You can do it too!" # Index 0 print(main_string[0]) # Index 1 print(main_string[1]) # Check if Index 1 is whitespace print(main_string[1].isspace()) # Slicing 1 print(main_string[0:11]) # Slicing 2: print(main_...
说2个好笑的: 1. 上图我标注的 Return the highest index in S where substring sub is found。 看到 有地方介绍 rfind()是 会返回某字符串最后一次出现的位置,我的第一想法:从右边开始 最后一次,那不就是 从左边 首次出现吗?好像不对呀。 然后才明白:那儿的意思是 从左边最后一次,不正是我想的从右边 ...
main_string="I learned English and Python with ZHouluobo. You can do it too!"# Index 0print(main_string[0])# Index 1print(main_string[1])# Check if Index 1 is whitespaceprint(main_string[1].isspace())# Slicing 1print(main_string[0:11])# Slicing 2:print(main_string[-18:])# ...
<bool> = in <str> # Checks if string contains the substring. <bool> = <str>.startswith() # Pass tuple of strings for multiple options. <int> = <str>.find() # Returns start index of the first match or -1. <int> = <str>.index() # Same, but raises ValueError if there's ...