# Program to check if a number is prime or notnum =29# To take input from the user#num = int(input("Enter a number: "))# define a flag variableflag =Falseifnum ==0ornum ==1:print(num,"is not a prime number")elifnum >1:# check for factorsforiinrange(2, num):if(num % ...
def multi_permission_check(checks): def decorator(func): def wrapper(*args, **kwargs): for check in checks: if not check(*args, **kwargs): raise PermissionError("Permission check failed.") return func(*args, **kwargs) return wrapper return decorator def is_admin(user): return user.g...
例如,我们可以编写一个装饰器来检查输入是否为正数: defcheck_positive(func):defwrapper(*args,**kwargs):ifany(arg<=0forarginargs):raiseValueError("Arguments must be positive.")returnfunc(*args,**kwargs)returnwrapper@check_positivedefdivide(a,b):returna/b 1. 2. 3. 4. 5. 6. 7. 8. 9....
Write a Python function to check whether a number is "Perfect" or not.According to Wikipedia : In number theory, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself (also k...
这样,我们就可以通过调用check_positive_negative_numbers函数来检查数据中的正/负数,并获得相应的结果。 对于这个问题,腾讯云没有特定的产品或服务与之直接相关。然而,腾讯云提供了一系列云计算服务,如云服务器、云数据库、云存储等,可以用于支持各种数据处理和应用场景。您可以访问腾讯云官方网站(https://cloud.tencent...
The class’s initializer, .__init__(), takes radius as an argument and makes sure that the input value is a positive number. This check prevents circles with a negative radius. The .area() method computes the circle’s area. However, before doing that, the method uses an assert stateme...
# Define a function to add two numbers represented as stringsdeftest(n1,n2):# Add '0' to the beginning of each input string to handle negative numbersn1,n2='0'+n1,'0'+n2# Check if both modified strings are numericif(n1.isnumeric()andn2.isnumeric()):# If true, convert the strings...
答案:defget_factors_sum(num):factors_sum=0foriinrange(1,num):ifnum%i==0:factors_sum+=ireturnfactors_sumdefmain():try:num=int(input("Enteraninteger:"))ifnum<=0:print("Pleaseenterapositiveinteger.")returnfactors_sum=get_factors_sum(num)iffactors_sum==num:print(f"{num}isaperfectnumber...
You may check the breaking results ofnranging from 7 to 10 to discover the regularities. https://leetcode.com/problems/integer-break/ 把一个数字拆成几个数字相加,这几个数的乘积要最大。 先是O(n^2)的动态规划。某个数最大的乘积,总是由比它小的数的子结果,乘以他们之间的差得来的。
defproduct(n,term):"""Return the productofthe first n termsina sequence.n--a positive integer term--afunctionthat takes one argument>>>product(3,identity)#1*2*36>>>product(5,identity)#1*2*3*4*5120>>>product(3,square)#1^2*2^2*3^236>>>product(5,square)#1^2*2^2*3^2*4^2...