Enter a number: 2 Positive number Output 2Enter a number: 0 Zero A number is positive if it is greater than zero. We check this in the expression of if. If it is False, the number will either be zero or negative. This is also tested in subsequent expression....
In this program, we ask the user for the input and check if the number is odd or even. Please note that { } is a replacement field for num. Also Read: Python Program to Check if a Number is Positive, Negative or 0 Before we wrap up, let's put your understanding of this example...
defcheck_number(num):ifnum<0:return"Number is negative"elifnum==0:return"Number is zero"else:return"Number is positive"result=check_number(10)print(result) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 在上面的例子中,check_number函数接收一个参数num,并根据num的值返回不同的结果。当num为正数时...
Write a Python program to determine if a given number is odd and a multiple of 7. Write a script that categorizes a number as "Even and Positive," "Odd and Positive," "Even and Negative," or "Odd and Negative." Write a program that accepts a number and prints all even or odd nu...
defcheck_number(number):ifnumber>0:return"Positive"elifnumber<0:return"Negative"else:return"Zero" 1. 2. 3. 4. 5. 6. 7. 在这个示例中,我们定义了一个名为check_number的函数,该函数接受一个参数number。根据number的值,函数会返回不同的字符串。如果number > 0,则返回"Positive";如果number < 0,...
What if you want to print the last character of a string but you don’t know how long it is?You can do that usingnegative indexes. In the example above, we don’t know the length of the string, but we know that the word ‘text’ plus the exclamation sign take five indices, so ...
Practice Problem: Check user input is a positive number or negative Show Solution user_number = input("Enter your number ") print("\n")try: val = int(user_number)ifval >0: print("User number is positive ")else: print("User number is negative ")exceptValueError: ...
27. ValueError: Sample larger than population or is negative import random a = [1, 2, 3, 4, 5] s = random.sample(a, 6) # 采样数据太多,多于总的数据。 print(a) 在使用随机库的时候,用它的采样函数,上面的例子采样数目多于总体的数目,因此报错。可以调整采样数目改正错误。
array([cos(rad), sin(rad)]) return c_res def sq3(c): # take the cubic root of a complex number, return a complex number rad = arctan(c[1]/c[0]) # range from -pi/2 to pi/2 # rad should be from -pi to pi if c[0]>0 and c[1]>0: rad = rad elif c[0]>0 and...
print("The new sum is: %i" % sum) # else if (可选,可以没有,也可以是多个elif分支) elif i==0: print("The sum did not change: %i" % sum) # 最后的else分支(可选)。 else: handle_error() # 死循环 while True: print("I got stuck forever!") ...