将上面的各个步骤整合在一起,我们就可以得到完整的代码: # 获取用户输入,并将其转换为整数num=int(input("请输入一个整数:"))# 判断是否能被2整除is_divisible_by_2=(num%2==0)# 判断是否能被3整除is_divisible_by_3=(num%3==0)# 输出结果ifis_divisible_by_2andis_divisible_by_3:print(f"{num...
# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
The most common approach to check if a number is even or odd in Python is using themodulo operator (%). The modulo operator returns the remainder after division. An even number is evenly divisible by 2 with no remainder, while an odd number leaves a remainder of 1 when divided by 2. ...
We check if num is exactly divisible by any number from 2 to num - 1. If we find a factor in that range, the number is not prime, so we set flag to True and break out of the loop. Outside the loop, we check if flag is True or False. If it is True, num is not a prime...
Check the said number is a Harshad number or not! True Flowchart: Sample Solution-2: Python Code: deftest(n):if(n>0):t=sum(map(int,str(n)))returnnotn%t n=666print("Original number:",n)print("Check the said number is a Harshad number or not!")print(test(n))n=11print("\...
LOW_PRIMES = primeSieve(100) def isPrime(num): # Return True if num is a prime number. This function does a quicker # prime number check before calling rabinMiller(). if (num < 2): return False # 0, 1, and negative numbers are not prime. # See if any of the low prime numbers...
Sample decimal number: 30, 4 Expected output: 1e, 04 Click me to see the sample solution 142. Consecutive Zero-One Checker Write a Python program to check if every consecutive sequence of zeroes is followed by a consecutive sequence of ones of same length in a given string. Return True/...
# Check if the video opened successfully if not cap.isOpened(): print(f"Error: Could not open video {video_path}") return frame_count = 0 saved_frame_count = 0 while True: # Read the next frame from the video ret, frame = cap.read() ...
2. check is number split by . or e, note that number after e may be negative 66 Plus One Python Check if current digit == 9. 70 Climbing Stairs Python Bottom-up DP, dp[i] = dp[i - 2] + dp[i- 1] 1. O(n) and O(n)2. Only two variables are needed, O(n) and O(1)...
2. 3. 4. 5. 6. 在这段代码中,使用if语句来判断上述条件,如果同时为真,则显示相应的消息。 类图表示 这段代码的逻辑可以用类图表示,尽管我们并没有使用类,但可以简化地将其表示为: NumberChecker+ number: int+ is_divisible_by_3: bool+ ends_with_3: bool+check_conditions() ...