samples = np.repeat(n,k) samples = np.append(samples, len(my_list) % n) else: samples = np.repeat(n,k) k = len(my_list) / n out = [] for s in samples: out.append(random.sample(my_list, s)) # remove the now sample elements from my_list return out x = repeated_sample_...
Check if Python List Contains Elements of Another List https://www.techbeamers.com/program-python-list-contains-elements/ Built-in Functions — Python 3.7.4 documentation https://docs.python.org/3/library/functions.html?highlight=any#any https://docs.python.org/3/library/functions.html?#al...
candidate=firstelse:series=iter(first)try:candidate=next(series)except StopIteration:ifdefaultis notMISSING:returndefaultraiseValueError(EMPTY_MSG)from Noneifkey is None:forcurrentinseries:ifcandidate<current:candidate=currentelse:candidate_key=key(candidate)forcurrentinseries:current_key=key(current)ifcandi...
The array (a tuple) has various numbers. You should sort it, but sort it by absolute value in ascending order. For example, the sequence (-20, -5, 10, 15) will be sorted like so: (-5, 10, 15, -20). Your function should return the sorted list or tuple. Hints:This task can ...
10.Find indices of non-zero elements from 1,2,0,0,4,0 nz = np.nonzero([1,2,0,0,4,0]) print(nz) 11.Create a 3x3 identity matrix (★☆☆) Z = np.eye(3) print(Z) 12.Create a 3x3x3 array with random values (★☆☆) ...
elements "bubble" to the top of the list. Although the algorithm is simple, it is too slow and impractical for most problems even when compared to insertion sort. It can be practical if the input is usually in sort order but may occasionally have some out-of-order elements nearly in ...
class Solution: def checkIfExist(self, arr: List[int]) -> bool: ''' n = len(arr) for i in range(n-1): for j in range(i+1,n): if arr[i] == 2 * arr[j] or 2 * arr[i] == arr[j]: return True return False ''' zero = False for i, e in enumerate(arr): if no...
If you want to repeat or duplicate the elements of Python tuples you can use the repetition concept. Example: Python 1 2 3 4 tuple1 = (1, 2, 3) result = tuple1 * 2 print(result) Output: 3. Membership Test in Python In order to check whether the particular element is present in...
Let’s say we have a list of numbers and we want to check if a number is present or not. We can iterate over the list of numbers and if the number is found, break out of the loop because we don’t need to keep iterating over the remaining elements. ...
if obj is None: return self.name = getattr(obj, 'name', "no name") Z = NamedArray(np.arange(10), "range_10") print (Z.name) ``` ### 64. Consider a given vector, how to add 1 to each element indexed by a second vector (be careful with repeated indices)? (★★★) `hint...