Enter a number: 0 Zero A number is positive if it is greater than zero. We check this in the expression of if. If it is False, the number will either be zero or negative. This is also tested in subsequent expression.Also Read: Python Program to Check if a Number is Odd or Even ...
Check if the input is a number using int() or float() in Python Theint()orfloat()method is used to convert any input string to a number. We can use this function to check if the user input is a valid number. If the user input is successfully converted to a number usingint()orfl...
If it is successful, then the function returns True. Else, ValueError is raised and returns False. For example, 's12' is alphanumeric, so it cannot be converted to float and False is returned; whereas, '1.123' is a numeric, so it is successfully converted to float. Also Read: Python ...
deftest(n):if(n>0):t=sum(map(int,str(n)))returnnotn%t n=666print("Original number:",n)print("Check the said number is a Harshad number or not!")print(test(n))n=11print("\nOriginal number:",n)print("Check the said number is a Harshad number or not!")print(test(n))n=...
print(is_even(42)) print(is_even(31)) Output: True False I have executed the above example code and added the screenshot below. In this code, theis_evenfunction takes a number as input and uses the modulo operator to check if it is divisible by 2. If the remainder is 0, the func...
# Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check if the remainder is greater than 0, indicating an odd numberifmod>0:# Print a message indicating that...
To check if the input is a float number, convert the user input to the float type using thefloat()constructor. Validate the result If an input is an integer or float number, it can successfully get converted tointorfloattype. Else, we can conclude it is a string ...
Check your installed dependenciesforsecurity vulnerabilities:$ pipenv check Install a local setup.py into your virtual environment/Pipfile:$ pipenv install-e.Use a lower-level pip command:$ pipenv run pip freezeCommands:check ChecksforPyUp Safety security vulnerabilities and againstPEP508markers providedi...
if i in a: print("找到了") else: print("没找到") 方法二:index a=["1","2","3"] a.index("1",0,3) #从下标0开始到3 左闭右开 找到了返回下标 没找到就报错 方法三:count a=["1","2","3"] print( a.count("1") ) #统计你要查找的元素的个数 ...
['Sam', 'Peter', 'Nancy', 'Alice'] class2 = ['Bob', 'David', 'June', 'Mary'] # Ask user to type in a student's name student = input("Please type the student's name here: ") # Check the student's class number if student in class1: print("Student {} is in Class 1....