使用位运算符 & 来判断一个数的最后一位是否为 0，如果是，则该数为偶数；否则，该数为奇数。使用数学方法 import mathdef check_odd_even(num):if int(num/2) == num/2:return"偶数"else:return"奇数"while 1: data = int(input("请输入一个数: ")) print("判断结果为：", check_odd_eve...
Checkifa numericvalue(int,float,etc.)is effectively zero.Args:-num:The numeric value to check.-tolerance:The tolerance levelforfloating-point comparisons.Returns:-bool:Trueifnum is effectively zero,False otherwise."""ifisinstance(num,int):# Integer checkreturnnum==0elifisinstance(num,float):# Fl...
elif int(orange_cnt) > 3 or int(banana_cnt) print("Orange or banana !") elif int(banana_cnt) > 8: print("Banana is your favorite!") else: print("Sorry...") corvin@workspace:~/python_tutorial$chmod +x if_and_or.py corvin@workspace:~/python_tutorial$./if_and_or.py Apple count...
(req: func.HttpRequest) -> func.HttpResponse: logging.info('Executing my_second_function.') initial_value: int = int(req.params.get('value')) doubled_value: int = my_second_helper_function.double(initial_value) return func.HttpResponse( body=f"{initial_value} * 2 = {doubled_value}...
Python3 method to check for float: def is_float(element: any) -> bool: #If you expect None to be passed: if element is None: return False try: float(element) return True except ValueError: return False Python2 version of the above: How do I parse a string to a float or int?
SQL_CREATE_TABLE = '''CREATE TABLE IF NOT EXISTS PEOPLE (ID INT PRIMARY KEY NOT NULL, NAME TEXT NOT NULL, AGE INT NOT NULL);''' def create_db_table(self): """ 初始化表 :return: """ self.conn.execute(SQL_CREATE_TABLE) 接下来,我们通过增删改查来操作数据表 1、新增 同样以新增单条...
defcheck_johansen(df): '''df是包含两个序列的dataframe''' #进行Johansen协整检验 johansen_test=coint_johansen(df.values,det_order=0,k_ar_diff=1) #判断是否存在协整关系 ifjohansen_test.lr1[0]>johansen_test.cvt[0,1]:#5%显著性水平 returnTrue else: returnFalse statsmodels库的coint函数返回三个...
if__name__ =='__main__': parser = argparse.ArgumentParser( description=__description__, epilog="Developed by {} on {}".format(", ".join(__authors__), __date__) ) parser.add_argument('EVIDENCE_FILE',help="Path to evidence file") ...
if hi is None:hi = len(a)pos = bisect_left(a, x, lo, hi) # 搜索插入位置 return pos if pos != hi and a[pos] == x else -1 print(binary_search([0, 1, 2, 5, 6, 8], 5)) # 3 print(binary_search([0, 1, 2, 5, 6, 8], 4)) # -1 实现一个binary_search函数，...
Python 数字取证秘籍(一) 原文:zh.annas-archive.org/md5/941c711b36df2129e5f7d215d3712f03 译者:飞龙 协议:CC BY-NC-SA 4.0 前言 在本书开始时,我们努力展示了 Python 在当今数字调查中几乎无穷无尽的用例。技术在我