Use the any() function to check if any element in a list meets a condition. The any function will return True if any element in the list meets the condition and False otherwise. main.py my_list = [1, 3, 5, 15] if any(item > 10 for item in my_list): # 👇️ this runs ...
A solution faster than using set() that works on sequences (not iterables) is to simply count the first element. This assumes the list is non-empty (but that's trivial to check, and decide yourself what the outcome should be on an empty list) x.count(x[0]) == len(x) some sim...
for value in values: if value not in lst: return False return True 示例 values_to_check = [1, 2, 3] a_list = [1, 2, 3, 4, 5] result = are_all_values_in_list(values_to_check, a_list) # 返回True 逐个元素比较方法虽然代码较为直接,但当列表和待判断的值都很多时,会因为多次遍历...
4. 判断列表中所有元素是否都是0 (python check if all element in list is zero) https://stackoverflow.com/questions/10666163/how-to-check-if-all-elements-of-a-list-matches-a-condition In [62]: b=[0, 0, 0, 0, 0, 0, 0, 0, 0] In [63]: all(i==0foriinb) Out[63]: True 5...
any() 函数接受一个可迭代对象,只要其中任何一个元素为真(即非零、非空、非None等),就返回 True。这个特性可以用于判定列表是否包含某个元素。#使用 any() 函数element_to_check = 3ifany(x == element_to_checkforxinmy_list):print(f"{element_to_check} 存在于列表中。")else:print(f"{element_to...
1 Checking if an item in a list is in another list 2 Efficient way to check if the last element in a row (in a list of lists) is found in another list? 1 Python If last N values of list is same as last N values of list 2 1 Check if element of list is sub-element of...
Python 判断元素是否在列表中存在 Python3 实例 定义一个列表,并判断元素是否在列表中。 实例 1 [mycode4 type='python'] test_list = [ 1, 6, 3, 5, 3, 4 ] print('查看 4 是否在列表中 ( 使用循环 ) : ') for i in test_list: if(i == 4) : ..
时间复杂度:O(n+m),其中n是list1的长度,m是list2的长度。 空间复杂度:O(k),其中k是两个列表中唯一元素的个数。 方法5:使用operator.countOf()方法 importoperatorasop# Python code to check if two lists# have any element in common# Initialization of listlist1=[1,3,4,55]list2=[90,1,22]...
if : found == true print "found" else : print "not found" Program to check if an element is present in the list # Python program to check if an# element exists in list# Getting list from usermyList=[]length=int(input("Enter number of elements: "))foriinrange(0,length):value=in...
To address this challenge to check if an element exists in Python Selenium while locating web elements, you can implement a solution that fits if an element exists before interacting with it. This approach helps in tracking and adapting to changes in the DOM content. While Selenium’s NoSuch...