Write a function to check if the entered integer is odd or even. If the given number is odd, return "Odd". If the given number is even, return "Even". For example, for input 4, the output should be "Even". 1 2 def odd_even(num): Check Code Share on: Did you find this...
Check if the input is a number using int() or float() in Python Theint()orfloat()method is used to convert any input string to a number. We can use this function to check if the user input is a valid number. If the user input is successfully converted to a number usingint()orfl...
importredefis_number(num):is_integer=bool(re.fullmatch(r"\d+",num))is_decimal=bool(re.fullmat...
n=666print("Original number:",n)print("Check the said number is a Harshad number or not!")print(test(n))n=11print("\nOriginal number:",n)print("Check the said number is a Harshad number or not!")print(test(n))n=-144print("\nOriginal number:",n)print("Check the said number...
Suppose we have a number n. We have to check whether n is Euclid number or not. As we know Euclid numbers are integer which can be represented as n= Pn+1 where is product of first n prime numbers. So, if the input is like n = 211, then the output will be True n can be ...
Example 2: Using a for...else statement num = 407 # To take input from the user #num = int(input("Enter a number: ")) if num == 0 or num == 1: print(num, "is not a prime number") elif num > 1: # check for factors for i in range(2,num): if (num % i) == 0:...
# Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check if the remainder is greater than 0, indicating an odd numberifmod>0:# Print a message indicating that...
问在python中使用.is_integer()时遇到问题EN我正在尝试开发一个python脚本，它循环遍历我拥有的一组子...
type of number class 'str' As you can see, The output shows the type of a variable as a string (str). Solution: In such a situation, We need toconvert user input explicitly to integer and floatto check if it’s a number. If the input string is a number, It will get converted ...
You can check if a variable is an integer using the type() function, passing the variable as an argument, and then comparing the result to the int class:age = 1 type(age) == int #TrueOr using isinstance(), passing 2 arguments: the variable, and the int class:...