下面是一个使用列表推导式判断字符串是否由数字和字母组成的Python代码示例: defis_alphanumeric(input_str):returnall(char.isalnum()forcharininput_str)# 测试示例print(is_alphanumeric('abc123'))# Trueprint(is_alphanumeric('abc'))# Trueprint(is_alphanumeric('123'))# Trueprint(is_alphanumeric('abc...
defis_alphanumeric(string):forcharinstring:ifnot(char.isalpha()orchar.isdigit()):returnFalsereturnTruestring ="abc123"print(is_alphanumeric(string))# 输出:Truestring ="abc123!"print(is_alphanumeric(string))# 输出:False 在这个示例中,我们定义了一个名为is_alphanumeric()的函数,它接受一个字符串...
defis_alphanumeric(string):forcharinstring:ifnotchar.isalpha()andnotchar.isdigit():returnFalsereturnTrue# 测试代码string1="Hello123"string2="Hello, World!"print(is_alphanumeric(string1))# 输出 Trueprint(is_alphanumeric(string2))# 输出 False 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. ...
def is_number(s): try: float(s) return True except ValueError: return Falseprint(is_number("123")) # 输出: Trueprint(is_number("12.3")) # 输出: Trueprint(is_number("abc")) # 输出: False14、将字符串转换为驼峰命名 将下划线命名法的字符串转换为驼峰命名法。def to...
| | Raises ValueError when the substring is not found. | | isalnum(...) | S.isalnum() -> bool | | Return True if all characters in S are alphanumeric | and there is at least one character in S, False otherwise. | | isalpha(...) | S.isalpha() -> bool | | Return True if...
center 返回宽度 width 的字符串,原字符串居中,两端填充fillchar的字符串 fillchar默认为空格 语法: >>> help(str.center) Help on method_descriptor: center(...) S.center(width[, fillchar]) -> str Return S centered in a string of length width. Padding is ...
whitespace string is a separator and empty strings are removed from the result. """ return [] 用法:返回字符串中所有单词的列表,使用 sep 作为分隔符(默认值是空字符(空格))用什么切就去掉什么。 可以使用 maxsplit 指定最大切分数。 例子: s = 'STriSSB' ...
| | Raises ValueError when the subsection is not found. | | isalnum(...) | B.isalnum() -> bool | | Return True if all characters in B are alphanumeric | and there is at least one character in B, False otherwise. | | isalpha(...) | B.isalpha() -> bool | | Return True ...
| Raises ValueError when the substring is not found. | | isalnum(...) | S.isalnum() -> bool | Return True if all characters in S are alphanumeric | and there is at least one character in S, False otherwise. | | isalpha(...) | S.isalpha() -> bool | Return True...
Like S.find() butraiseValueError when the substringisnotfound. """ return 0 def isalnum(self): """是否是字母和数字""" """ S.isalnum()->bool ReturnTrueifallcharactersinS are alphanumeric andthereisat least one characterinS,Falseotherwise. ...