被调用的函数(dostuff)或函数向下的函数本身可能有一个您没有/无法解释的KeyboardInterrupt或BaseException的catch. 这个简单的案例适用于python 2.6.6(x64)交互式+ Windows 7(64位): AI检测代码解析 >>> import time >>> def foo(): ... try: ... time.sleep(100) ... except KeyboardInterrupt: ......
Use thetry...exceptStatement to Catch theKeyboardInterruptError in Python Thetry...exceptstatement is used when it comes to the purpose of exception handling in Python. Thetry...exceptstatement has a unique syntax; it is divided into three blocks, all of which have a different purpose and ...
python exception try-catch 我有以下代码:import time try: time.sleep(3) raise Exception('error') except Exception or KeyboardInterrupt: print(">>> Error or keyboard interrupt") 我想捕捉错误或键盘中断。但目前,它只捕获一个异常,键盘中断未被处理。如果我删除异常并只留下键盘中断,它只捕获键盘中断。
AI代码解释 classMyCriticalError(BaseException):passtry:raiseMyCriticalError("A critical error")except Exceptionase:print("This will not catch MyCriticalError") 19、优雅的处理用户和系统中断 捕获KeyboardInterrupt和SystemExit异常,以优雅地处理用户或系统启动的关机。 代码语言:javascript 代码运行次数:0 运行 ...
Question 15: Fill in the blanks in this code to catch KeyboardInterrupt and stop the program gracefully: try: while True: print("Processing...") except ___: print("Terminating...") ▼ Question 16: What happens if a user sends an interrupt signal (e.g., Ctrl+C) while the program ...
catch_count += 1 print ('wait:', catch_count) if catch_count > 3: # recover handler for signal.SIGINT signal.signal(signal.SIGINT, default_handler) print('expecting KeyboardInterrupt') signal.signal(signal.SIGINT, handler) print('Press Ctrl+c here') ...
该程序从一个主类运行，该类调用几个模块和函数直接上代码： # encoding: UTF-8 import threading ...
例外，您知道，避免捕捉所有异常并吞噬它们。抛出的异常应该解释为什么，有时您知道异常类型不能被猜测。避免在catch语句块中做一些毫无意义的事情。不要使用异常来控制进程，这样您的程序就很难理解和维护。如果有需要，记得使用最后释放资源。如果您需要它，在处理异常后不要忘记清理或回滚。异常的查找表 一张动图宕...
BaseException除了包含所有的Exception外还包含了SystemExit,KeyboardInterrupt和GeneratorExit三个异常。 有此看来你的程序在捕获所有异常时更应该使用Exception而不是BaseException,因为另外三个异常属于更高级别的异常,合理的做法应该是交给Python的解释器处理。 except Exception as e和 except Exception, e 代码示例如下: ...
sleep(0.1) print("") def func(): try: raise KeyboardInterrupt wait("func", 10) except KeyboardInterrupt: print("catch on func") if __name__ == "__main__": print("start") for i in range(3): wait("main", 10) func() print("after func") print("end") 関数内で起こった...