def date_range(start, end): delta = end - start # as timedelta days = [start + ...
['date'] = pd.to_datetime(df.date)def calculate_days(date): today = pd.Timestamp('today') return (today - date).daysdf['days'] = df['date'].apply(lambda x: calculate_days(x)) Or: df['date'] = pd.to_datetime(df.date)def calculate_days(date): today = pd.Timestamp('today...
datetimeFormat)\-datetime.datetime.strptime(date2, datetimeFormat)print("Difference:", diff)print("Days:", diff.days)print("Microseconds:", diff.microseconds)print("Seconds:", diff.seconds)
- datetime.datetime.strptime(date2, datetimeFormat)print("Difference:", diff)# Difference: 37 days, 0:05:00.518000print("Days:", diff.days)# Days: 37print("Microseconds:", diff.microseconds)# Microseconds: 518000print("Seconds:", diff.seconds)# Seconds: 300 九、将 5 分钟添加到 Unix 时间...
['maturity'])# to get fractional years, we calculate difference in days and divide# by the average number of days per year:metric_df['term'] = (metric_df['maturity'] - pd.Timestamp("2021-10-15")).dt.days / 365.25 metric_df['term']0 3.9370291 12.0711842 1.374401Name: term, dtype...
%S.%f' date1 = '2016-04-16 10:01:28.585' date2 = '2016-03-10 09:56:28.067' diff = datetime.datetime.strptime(date1, datetimeFormat)\ - datetime.datetime.strptime(date2, datetimeFormat) print("Difference:", diff) print("Days:", diff.days) print("Microseconds:", diff.microseconds) ...
import math import ephem from datetime import datetime, timedelta,time from typing import Union #计算指定时间范围内日行迹(analemma)的数据 def calculate_analemma_positions(start_date:datetime, end_date:datetime,observer_latitude:Union[str, float]=34.545811,observer_longitude:Union[str, float]=108.925825...
today = date.today() for i in range(7): d = today - timedelta(days=i) if d.weekday() < 5: print(d) 1. 2. 3. 4. 5. 6. 7. 8. 9. 十三、从今天的日期和一个人的生日推算年龄 from datetime import date def calculate_age(born): ...
Python_Calculate期初、期末贷款余额 Python数组的dictionary.values() python argparse limit arg values操作API? Python -How自动执行浏览器提示? python中字符串的dict_values Python Pandas Period Date difference in * MonthEnds>,如何将其转换为int值
true_solar_time = calculate_true_solar_time(date_local,observer_latitude,observer_longitude) difference_in_days = (true_solar_time - start_date).days # 1900年1月1日是甲戌日: gan_index = (difference_in_days + 0) % 10 # 加0位 zhi_index = (difference_in_days + 10) % 12 # 加10位...