for 变量列表 in 可迭代对象: 语句块1 else: 语句块2 说明: else子句部分可以省略(用while语句类似) 当在循环语句内部用break终止循环时,else子句部分的语句不会执行 1 2 3 4 5 6 7 8 # 示例: # 此示例示意for语句订语法和用法 s="ABCDE" forchins: print("ch绑定--->".ch) else: print("for语...
\n")for number in range(100): if (number%3 ==2) and (number%5 ==3) and (number%7 ==2): # 判断是否符合条件 print("答曰：这个数是",number) # 输出符合条件的数 运行程序，输出结果如下：今有物不知其数，三三数之剩二，五五数之剩三，七七数之剩二，问几何？答曰：这个数...
for i in range(3): if i == 2: break print(i, end=' ') # 打印0和1 else: print("Loop completed without encountering a 'break' statement.")5.循环控制语句：range()函数：生成一个起始默认为0的序列，通常与for循环一起使用。def print_numbers(n): for i in range(1, n+1): print(i)...
python for-loop if-statement user-interface 嗯,我还在学习,现在我进入pyqt5 designer,但是我对for和if语句有一个问题,其中python不执行else或if,我使用print(empleados[i][“Nombre”])来检查else是否正在运行,但if或else没有运行 for i in range(0,len(empleados)): print(empleados[i]["Numero"]) i...
Python中if语句的一般形式如下所示: if condition_1: statement_block_1 elif condition_2: statement_block_2 else: statement_block_3 如果"condition_1" 为 True 将执行 "statement_block_1" 块语句 如果"condition_1" 为False,将判断 "condition_2" ...
languages = ['Swift','Python','Go','C++']forlanginlanguages:iflang =='Go':breakprint(lang) Run Code Output Swift Python Here, whenlangis equal to'Go', thebreakstatement inside theifcondition executes which terminates the loop immediately. This is whyGoandC++are not printed. ...
Python for loop with string The following example uses Pythonforstatement to go through a string. for_loop_string.py #!/usr/bin/python word = "cloud" for let in word: print(let) We have a string defined. With theforloop, we print the letters of the word one by one to the terminal...
break 跳出，即 while 循环正常结束，程序将进入到可选的 else 段。while...else 有点类似于 if.....
根据Python的缩进规则,如果if语句判断是True,就把缩进的两行print语句执行了,否则,什么也不做。 可以通过下图来简单了解条件语句的执行过程: if 语句 Python中if语句的一般形式如下所示: ifcondition_1:statement_block_1elifcondition_2:statement_block_2else:statement_block_3 ...
Python:If语句在for循环下不工作 python for-loop if-statement list = ["Donald, Trump", "Joe, Biden", "Barack, Obama"] while True: name = input("Name: ") for short in list: if name in short[0]: print("It Work") else: print("It Don't Work") 它应该打印“It Work”,因为我...