# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
> [0, 1, 1, 2, 3, 5, 8, 13, 21, 34] ▍49、编写程序,检查数字是否为Armstrong 将每个数字依次分离,并累加其立方(位数)。 最后,如果发现总和等于原始数,则称为阿姆斯特朗数(Armstrong)。 from collections import Counter def word_count(fname): with open(fname) as f: return Counter(f.read()...
ProgramUserProgramUser输入数字和幂数判断数字是否是自幂数返回判断结果 在测试过程中,用户将输入数字和幂数,程序将判断数字是否是自幂数,并将判断结果返回给用户。 我们来编写一个简单的交互式程序来测试我们的函数: defmain():num=input("请输入一个数字:")n=int(input("请输入幂数:"))ifis_armstrong_number(n...
Step 5: Determine if the number is equal to the entry number.Step 6: If equal, print as Armstrong number. Otherwise, do not write the Armstrong number.Program to Find Armstrong Number of n DigitsUsing For loop:def is_armstrong_number(number): num_str=str(number) num_digits=len(num_str...
#Python program to check 3 Digits Armstrong Number#Taking input from usernum =int(input("Enter a number: "))# Declarign and intilizing sum variablearsum =0#Coping orignal value into a temp veriablet = num#While loop for iteration till t is greater than 0whilet >0:#if Yes#Applying Mo...
▍49、编写程序,检查数字是否为Armstrong 将每个数字依次分离,并累加其立方(位数)。 最后,如果发现总和等于原始数,则称为阿姆斯特朗数(Armstrong)。 from collections import Counter def word_count(fname): with open(fname) as f: return Counter(f.read().split()) ...
"is an Armstrong number") else: print(num,"is not an Armstrong number")“Compile”：编译...
num = int(input("Enter the number:\n")) order = len(str(num)) sum = 0 temp = num while temp > 0: digit = temp % 10 sum += digit ** order temp //= 10 if num == sum: print(num,"is an Armstrong number") else:
答案:defis_armstrong_number(num):num_str=str(num)num_digits=len(num_str)total=0fordigit_charinnum_str:digit=int(digit_char)total+=digit**num_digitsreturntotal==numdefmain():armstrong_numbers=[]fornuminrange(100,1000):ifis_armstrong_number(num):armstrong_numbers.append(num)print("All...
print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number") ▍50、用一行Python代码,从给定列表中取出所有的偶数和奇数 1 2 3 4 5 a = [1,2,3,4,5,6,7,8,9,10] odd, even = [el for el in a if el % 2==1], [el for el in a if el % 2==0] ...