tuple(iter):将可迭代对象iter转换成元组。 str(obj):将对象obj转换成字符串。 list()和tuple()函数比较常用,常用于列表和元组数据的类型转换,参数不仅可以是序列对象,还可以是一切可迭代对象。 print(list("Hello Shuangying Yan")) print(tuple("Ying")) print(list((1, 2, 3))) print(tuple([1, 2,...
我们发现元组的输出结果和列表的输出结果是完全一样的,我们再来看一下列表和元组的不同之处: 1 list = ['python', 786, 2.23]2 tuple = ('python', 786, 2.23)3 list[1] = 1000 4 print(list) #1000 5 tuple[1] = 1000 6 print(tuple) #TypeError: 'tuple' object does not support item assig...
To add an item to the end of the list, use theappend()method: ExampleGet your own Python Server Using theappend()method to append an item: thislist = ["apple","banana","cherry"] thislist.append("orange") print(thislist) Try it Yourself » ...
tuple = ("python", "includehelp", 43, 54.23) Adding a dictionary to tupleIn this problem, we are given a tuple and a dictionary. We need to create a Python program that will add the dictionary as an element to the tuple.Input: ('programming', 'language', 'tutorial') {1 : '...
defadd(self, *args, **kwargs):"""Add an element to a set. This has no effect if the element is already present."""pass给集合添加一个元素,当元素已存在时,集合不变。defclear(self, *args, **kwargs):"""Remove all elements from this set."""pass清空集合,删除所有元素。defcopy(self,...
错误提示: 修改tuple时,提示TypeError: ‘tuple’ object does not support item assignment 可能原因: 1、tuple内的元素是不可以修改的,除非tuple内部再嵌套了list,可以修改list内部的元素 解决方法: 1、tuple不能修改元素,无解。如果要修改元素,改用list类型。
Now, I will show you how to add a string to the list using the different methods. As you know, a string is a collection of characters. Add String to List Python using append() Method The list object has a method called append() which allows you to append the item to the list. ...
lst.append(element)lst[len(lst)+1:] = [element]Add an item to the end of the list lst.extend([elements])lst[len(lst)+1:] = [elements]Add multiple elements to the end of the list lst.insert(index, element)lst[index:index] = [element]Add an element before the given index ...
self.word_list.addItems(words)defon_item_changed(self, curr, prev):word = curr.text() card = find_card_by_word(self.cards, word) self.card_edit_widget.show_card(card) 开发者ID:OlgaRa,项目名称:lang-tutor,代码行数:35,代码来源:card_list_widget.py ...
immutable_fruits=frozenset({'apple','banana'})# 尝试向不可变集合添加元素,将会引发错误immutable_fruits.add('orange')# TypeError: 'frozenset' object does not support item assignment 2.3 集合元素的要求 集合中的元素必须是不可变的,这意味着字符串、数字、元组(只要元组内的元素也是不可变的)可以作为集合...