答案:[4, 8, 12, 16, 20] 题目:请编写一个Python函数,实现计算一个整数列表的平均值。 ```python def calculate_average(numbers): sum = 0 for num in numbers: sum += num average = sum / len(numbers) return average numbers = [1, 2, 3, 4, 5] print(calculate_average(numbers)) ```...
def num_list():list=[1,2,3,4]list1=[]for i in list:for j in list:if i==j:continue for k in list:if(i==k)or(j==k):continue for n in list:if(i==n)or(j==n)or(k==n):continue num=1000*i+100*j+10*k+n list1.append(num)return list1 def sushu(num):...
print(result)运行:请输入一串数字1,2,3,4,5,6 start3 end5 3,4,5
total=sum([i*(i+1)*(i+2) for i in range(1,100,2)])print(total)
s = 0 for i in range(1,100):s = s + i*(i+1)*(i+2)print(s)S = 25497450
问题：计算1*2*3 + 3*4*5 + ... + 99*100*101 程序代码：sum = 0 i = 1 while i < 100:sum += i * (i + 1) * (i + 2)i += 2 print(sum)运行结果：13002450
python编写程序,输出1*2*3+3*4*5+5*6*7+...+99*100*101的值? sum([i*(i+1)*(i+2) for i in range(1,100,2)])
res = 0 for i in range(1, 100):cur = i for j in range(1, 2):cur *= (i + j)res += cur print(res)
火柴棍游戏用火柴棍拼成数字 0~9,具体拼法如图所示:编写 Python 程序,实现输入火柴棍的数量,输出符合该火柴棍数的三位数组合,若找不到,则输出“没有符合要求的数”,见样例,程序如下:请在划线处填入合适代码。code={0:6,1:2,2:5,3:5,4:4,5:5,6:6,7:3,8:7,9:6}num=int
①两数m、n交换(用大数翻倍),m,n=n,m,故填n,m;②最大公倍数初始值设为较大数,如果能整除,则较大数就是最小公倍数;如果不能整除,则让较大数乘以2,3,4...递增1的自然数,直到能整除为止。故循环条件是s不能整除n,故填s%n!=0;③让较大数乘以2,3,4...递