list2 = [(\'something\',\'othervalues\'),(\'suzy\',\'stuff\'),(\'bobby\',\'otherthings\')] 然后,我将在list1中每个元组的第一个元素上收到输出soring。 sorted = [(\'suzy\',\'stuff\'),(\'something\',\'othervalues\'),(\'bobby\',\'otherthings\') ] 因此,基本上,它执行交集...
('B',[(1.23, 'fine'),(1.50, 'thanks'),(1.6,'and you')]), ('C',[(2.12,'good'),(2.24,'morning'),(3.13,'guys')])] Desired Output: [('A', ( 0.12, 'how')), ('A', ( 0.26, 'are')), ('A', ( 0.7, 'you')), ('A', ( 0.9, 'mike')), ('B',(1.23, 'fine...
sample = [(2, 6, 4, 5), (1, 7), (4, 3, 4), (2, 3, 8, 1), (4,)]sample.sort(key=lambda x: len(x))sample.sort(key=lambda x: sum(x)/len(x))第一次根据元组长度排序,保证长度较短的元素相对位置靠前(如果没有长度排序,直接进行平均值排序,元素 (1, 7) 会排...