因此不能使用点.表示法'如col1.Lat'，因为此表示法适用于struct数据类型，而不是string ...
Can't extract value from ce_data#12747: need struct type but got string; So, I would first need to understand why I'm not seeing the arrays in the printSchema(), however my main question is how to query arrays in JSON using sparkSQL. I'm also wondering if I ...
MapType Demo from pyspark.sql.types import * def word_count(input_string): word_dict = {} word_list = input_string.split(' ') for word in word_list: word_dict[word] = 0 for word in word_list: word_dict[word] += 1 return word_dict spark.udf.register('word_count', word_coun...
`returnType` 默认是 string type 并且可以按需指定. 返回类型必须匹配指定类型. 这种情况约等于 `register(name, f, returnType=StringType())`. >>> strlen = spark.udf.register("stringLengthString", lambda x: len(x)) >>> spark.sql("SELECT stringLengthString('test')")....
StructField("id", StringType(), True), \ StructField("gender", StringType(), True), \ StructField("salary", IntegerType(), True) \ ]) df = spark.createDataFrame(data=data2,schema=schema) df.printSchema() df.show(truncate=False) ...
你得到这个错误的原因是因为reportData中的一些记录由字符串组成。所以它把所有的记录类型作为字符串类型，...
我想你可以检查一下df.columns，然后dynamically在struct中包含所需的列，并使用to_json函数创建一个json...
importstringdefconvert_ascii(number):return[number,string.ascii_letters[number]]convert_ascii(1) [1, 'b'] array_schema=StructType([StructField('number',IntegerType(),nullable=False),StructField('letters',StringType(),nullable=False)])spark_convert_ascii=udf(lambdaz:convert_ascii(z),array_schema...
need to build it your own :), with maven and profile assembly which builds fat jar in jvm-packages/xgboost-spark/target or so. wpopielarski commented Jun 20, 2018 @sagnik-rzt not sure what you are going to do but to build fat jar for your OS just clone dmlc xgboost github project...
mySchema=StructType([ StructField("Source", StringType(),True) ,StructField("Entity", StringType(),True) ,StructField("Attribute", StringType(),True) ,StructField("Value", StringType(),True)]) df=spark.createDataFrame(metadataList, schema=mySchema) ...