pyspark 将嵌套结构字段转换为Json字符串原来，为了追加/删除/重命名嵌套字段，您需要更改模式。我不知道这一点。下面是我的答案。我从这里https://stackoverflow.com/a/48906217/984114复制并修改了代码，以便使其能够与我的模式一起工作 下面是“exclude_nested_field”的修改版本 我需要一个通用的解决方案来处理任意级别的嵌套列强制转换。
df[column] = df[column].apply(json.loads) return df def ct_val_to_json(value): """Convert a scalar complex type value to JSON Args: value: map or list complex value Returns: str: JSON string """ return json.dumps({'root': value}) def cols_to_json(df, columns): """Converts ...
How to export Spark/PySpark printSchame() result to String or JSON? As you know printSchema() prints schema to console or log depending on how you are running, however, sometimes you may be required to convert it into a String or to a JSON file. In this article, I will explain how ...
from pyspark.sql.types import DoubleType, StringType, IntegerType, FloatType from pyspark.sql.types import StructField from pyspark.sql.types import StructType PYSPARK_SQL_TYPE_DICT = { int: IntegerType(), float: FloatType(), str: StringType() } # 生成RDD rdd = spark_session.sparkContext....
override def convert(obj: Any): String = { val result = obj.asInstanceOf[Result] val output = result.listCells.asScala.map(cell => Map( "row" -> Bytes.toStringBinary(CellUtil.cloneRow(cell)), "columnFamily" -> Bytes.toStringBinary(CellUtil.cloneFamily(cell)), ...
column 可以是String, Double或者Long等等。...使用inferSchema=false (默认值) 将默认所有columns类型为strings (StringType).。取决于你希望后续以什么类型处理, strings 有时候不能有效工作。 24610 spark 数据处理 -- 数据采样【随机抽样、分层抽样、权重抽样】 ...
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sc.parallelize([rowNum, column_family, column_quality, value]).map(lambda x: (x[0], x)),其实Convert接收的一个多为数组,但是如果是上述定义,参数是String。 解决的方式:百思不得其解之际,因为有成功案例(只不过对于成功案例理解不深),于是我尝试仿照成功案例的写法,而不是自己的理解的写法,将sc.paral...
Create a DataFrame called by_plane that is grouped by the column tailnum. Use the .count() method with no arguments to count the number of flights each plane made. Create a DataFrame called by_origin that is grouped by the column origin. Find the .avg() of the air_time column to fin...
The following example shows how to convert a column from an integer to string type, using the col method to reference a column:Python Копирај from pyspark.sql.functions import col df_casted = df_customer.withColumn("c_custkey", col("c_custkey").cast(StringType())) print(...