def convert_to_binary(string_list): binary_list = [string.encode('utf-8') for string in string_list] return binary_list # 注册UDF binary_udf = udf(convert_to_binary, ArrayType(BinaryType())) # 使用UDF转换字符串列表为二进制列表 df = df.withColumn("binary_col", binary_udf(df.string...
def tax(salary): """ convert string to int and cut 15% tax from the salary :param salary: The salary of staff worker :return: """ return 0.15 * int(salary) 将tools文件夹压缩后上传至OSS中。本文示例为tools.tar.gz。 说明 如果依赖多个Python文件,建议您使用gz压缩包进行压缩。您可以在Pytho...
Suppose I stick with Pandas and convert back to a Spark DF before saving to Hive table, would I be risking memory issues if the DF is too large? Hi Brian, You shouldn't need to use exlode, that will create a new row for each value in the array. The reason max ...
而不是一个字符串。如果需要，可以在convert pyspark dataframe column from list to string中找到如何...
如果你想获取JSON字符串，可以像这样使用struct+to_json：
class HBaseResultToStringConverter extends Converter[Any, String] { override def convert(obj: Any): String = { val result = obj.asInstanceOf[Result] val output = result.listCells.asScala.map(cell => Map( "row" -> Bytes.toStringBinary(CellUtil.cloneRow(cell)), ...
你的输出与输入相比不好。无论如何修改输入。让我知道这是否是你想要的 使用translate替换角括号。用逗号...
def tax(salary): """ convert string to int then cut 15% tax from the salary return a float number :param salary: The salary of staff worker :return: """ return 0.15 * int(salary) Compress and upload the tools folder to OSS. In this example, the folder is compressed to the tools....
sprintf 是个变参函数，定义如下： int sprintf( char *buffer, const char *format [, argument] ....
The following example shows how to convert a column from an integer to string type, using the col method to reference a column:Python Копирај from pyspark.sql.functions import col df_casted = df_customer.withColumn("c_custkey", col("c_custkey").cast(StringType())) print(...