Recall that,secx=1cosxand... Learn more about this topic: When to Use the Quotient Rule for Differentiation from Chapter 8/ Lesson 8 85K The quotient rule can be used for differentiation when taking the derivative of a function divided by another function. ...
To evaluate the derivative of {eq}\csc x {/eq}, first, we apply the trigonometry relation {eq}\csc(x)=\dfrac{1}{\sin x} {/eq} and then we 'll apply the quotient rule of derivative which is given below: {eq}\dfrac{\mathrm{d} }{\mathrm{d} x}\left ( \dfrac{u}{v} \...
An=∫baf(x+yn)g(x)dxA=∫baf(x)g(x)dx.An=∫abf(x+yn)g(x)dxA=∫abf(x)g(x)dx. Then since both functions are nice so that both integrals exist, we have |An−A|=∣∣∣∫ba(f(x+yn)−f(x))g(x)dx∣∣∣≤∫ba|f(x+yn)−f(x)||g(x)|dx.|An−...
prove the derivative of ln(x) 21.1.2025, 视频播放量 18、弹幕量 0、点赞数 3、投硬币枚数 0、收藏人数 1、转发人数 0, 视频作者 Bruce-Claire, 作者简介 Born in June 2016, Claire's happy life.,相关视频:2024中国高考数学最后一题的直觉化解释 13.6.2024,How to pr
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NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
The derivative of a function f is defined as follows: {eq}f'(a) = \lim{x\to a} \frac{f(x)-f(a)}{x-a} {/eq} Whenever a limit takes the form of a derivative of a function, we can compute the limit by computing the derivative of the function with known deriv...
If the derivative of a function f is f'(x) = (x - 2)^2 (x + 4)^7 x^4 then f is decreasing on the interval (A) (0, 2) (B) (2, infinity) (C) (- infinity, -4) (D) (-4, 0) (E) none of (A) to (D) Prove or disprove...
Homework Statement A function f(x) has a periodic derivative. In other words f ' (x + p) = f ' (x) for some real value of p. Is f(x) necessarily...
The second derivative is a negative constant. Hence, x = a/2 is indeed the point of maximum.] However, the problem is that I got the proof for two addends. But what if they are more? (Three, four, and so on.) I am afraid we may obtain a function of two...