This program takes two positive integers and calculates GCD using recursion. Visit this page to learn how you can calculate the GCD using loops. Example: GCD of Two Numbers using Recursion fun main(args: Array<String>) { val n1 = 366 val n2 = 60 val hcf = hcf(n1, n2) println("G....
n2 : -n2; while(n1!=n2) { if(n1 > n2) n1 -= n2; else n2 -= n1; } printf("GCD = %d",n1); return 0; } Output Enter two integers: 81 -153 GCD = 9 You can also use recursion to find the GCD.Share on: Did you find this article helpful?
Problem Solution: In this program, we will create a recursive function to calculate the GCD and return the result to the calling function. Program/Source Code: The source code to calculate the GCD using recursion is given below. The given program is compiled and executed successfully. // Rust...
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* C Program to Print Diamond Pattern using recursion */ #include <stdio.h> voidprintMul(chara,intn) { for(inti=0;i<n;i++) printf("%c ",a); } voidprintDiamond(inta,intb) { printMul(' ',a-1); printMul('*',2*b+1); ...
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In this example, you will learn to find the GCD of two numbers using two different methods: function and loops and, Euclidean algorithm
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