错误的命名空间或类名:如果更改了命名空间或类名,确保在Main方法中正确引用了启动类。 进一步资源 Microsoft Docs: Main() and Command-Line Arguments:了解如何在C#中编写Main方法及其参数。 Stack Overflow: Program does not contain a static 'Main' method suitable for an entry point:在Stack Overflow上搜索相...
article_id=391&type=article 修改办法,对着项目右键-》属性-》application-》output type设为Class Library即可。
你的第一张代码里面，少了Main()主函数。你可以先定义一个sunNumber()函数，但是接下来要在主函数Main()里面调用才行。试试增加Main()主函数进去看看行不行。如范例：一个项目的输出类型如果设置成了类库，就不能设置为启动项目了，类库自己是不能单独运行的。要使用这个类库，必须再建立一个输出类型...
Docker环境编译.Net6项目,出现诡异的CS5001 Program does not contain a static 'Main' method suitable for an entry point 排查 从报错信息看是Program.csMain 方法找不到查看后没什么问题,都是默认的创建的看来不是这里的问题 经过一番Google后找到这个 https://stackoverflow.com/questions/9607702/does-not-co...
其他这些回答说得这么复杂做什么！你检查一下下面我说的这个内容是不是正确的 1、从新建的项目中复制一个过来；2、右击复制过来的App.xmal-属性;3、把“生成操作”改为ApplicationDefinition；“自定义工具”改为MSBuild:Compile 4、保存即可；你...
been problematic. While it finally builds. we get the "error CS5001: Program does not contain a static 'Main' method suitable for an entry point" and the app doesn't launch. We followed this guide to add some relevant options but upon various rounds of tweaking we are not much further....
\r\n not working! \t is not working but \n does #C code to Read the sectors on hard disk 1>CSC : error CS5001: Program does not contain a static 'Main' method suitable for an entry point 2 Methods same signature but different return types 255 character limit OleDB C# - Inconsisten...
public static void main(String[] args) { ... } This is the main method. Every application in Java must contain the main method. The Java compiler starts executing the code from the main method. How does it work? Good question. However, we will not discuss it in this article. After ...
The only drawback to putting all the debugging information into the executable file is using additional disk space. The program does not run more slowly, because the debugging information is not loaded into the process image at run time. ...
WPF项目编译时出现“Program '*' does not contain a static 'Main' method suitable for an entry point”错误, 解决方法: 自定义一个静态入口 然后 项目属性 -》 应用程序 -》启动对象 ,选择新创建的这个静态类 示例代码: 1 2 3 4 5 6 7