This time, you are supposed to find A×B where A and B are two polynomials. Input Specification Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: where K is the number of nonzero terms in thepolynomial, Ni an...
PAT 甲级测试题目 -- 1009 Product of Polynomials 题目链接坑点:注意系数可能为负数!!只有测试点 0 过不去可能就是因为这个!!!我最初在做这道题的时候用了两种思路,一种将保存结果的数组初始化为 0,把乘积加上去,顺便记录下最后一个指数的值。用两次 2000 次 for 循环过滤掉 0 值以及输出答案,这个代码过...
Product of Polynomials【PAT 1009题】 题目链接:http://pat.zju.edu.cn/contests/pat-practise/1009 这道题是前面A+B for Polynomials的升级版,求两个多项式的和,由于有前车之鉴,所以这道题我注意了结果为0的项,其实我是用了一个通用的方式来处理结果,所以提交的时候并没有被什么陷阱绊住,首先,A*B,两项...
【PAT 甲级】1009 Product of Polynomials (25分)(模拟) 题目 多项式相乘,输入有两行,分别代表两个多项式的指数 exponent,和系数 coefficient。 分析 按题目模拟,两个循环。注意系数不为零的部分。 #include <bits/stdc++.h> using namespace std; #define db(x) cout<<x<<endl typedef long long ll; cons...
1009 Product of Polynomials 折腾半天ac不了,试了图中的例子,非零项计数出错,还以为是浮点数比较出了问题,想fabs()再与const float ZERO=1e-6比较判断是否为0 然鹅。。。 partially accected的主要原因是,只考虑了原先这个幂次的系数是不是0,没有在运算后在判断一下是否为0。
This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK ...
1009 Product of Polynomials (25 分)(模拟) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the inf......
模拟。关键符号说明: SymbolExplanationnA/nBNumber of terms in A/BfactorCoefficient of the term wi...
PAT 甲 1009 多项式乘积 Product of Polynomials This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:K N ?1 ?? a ?N ...
给出两个多项式,每个输入格式是 非零项个数 指数1 系数1 指数2 系数2 让计算两多项式的乘积,并按照指定格式输出非零项个数 指数1 系数1 指数2 系数2 要求顺序是指数从高到低。 思路 前面写过一个多项式求和的题 PAT 1002 A+B for Polynomials (25分),两个思想以及处理方式是一样的,只不过一个是加法,...