def productExceptSelf(nums): n = len(nums) res = [1]*n ## left product lp = 1 for i in range(n): res[i]=lp lp = lp*nums[i] ## right product rp = 1 for i in range(n-1, -1, -1): res[i] = res[i] * rp rp = rp*nums[i] return res 举例说明 为了更清楚地解释...
[LeetCode] 238. Product of Array Except Self Given an arraynumsofnintegers wheren> 1, return an arrayoutputsuch thatoutput[i]is equal to the product of all the elements ofnumsexceptnums[i]. Example: [1,2,3,4] [24,12,8,6] Note: Please solve it without division and in O(n). Fo...
Given an arraynumsofnintegers wheren> 1, return an arrayoutputsuch thatoutput[i]is equal to the product of all the elements ofnumsexceptnums[i]. Example: [1,2,3,4] [24,12,8,6] Note: Please solve it without division and in O(n). Follow up: Could you solve it with constant spac...
Description Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4]…
代码: class Solution(object): def productExceptSelf(self, nums): n = len(nums) res = [1] * n temp = 1 for i in range(0, n - 1): res[i + 1] = res[i] * nums[i] for i in range(n - 1, 0, -1): res[i] *= temp ...
LeetCode-Java-238. Product of Array Except Self,题目Givenanarraynumsofnintegerswheren>1,returnanarrayoutputsuchthatoutput[
Given an array nums ofnintegers wheren> 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. ...
238. Product of Array Except Self Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6]...
Can you solve this real interview question? Product of Array Except Self - Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i]. The product of any prefix or suffix of
[LeetCode]238.Product of Array Except Self 题目 Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n)....