给你一个整数数组 nums,返回一个数组 answer,其中 answer[i] 是nums 中除nums[i] 之外其余各元素的乘积。 要求: 时间复杂度为O(n) 空间复杂度 O(1) (不包括输出使用的存储) 不能使用除法 解题思路:左乘积*右乘积 两次遍历数组来解决问题。具体步骤如下: 使用一个数组 left 存储每个元素左边的乘积。 使用...
238. Product of Array Except Self java solutions Given an array ofnintegers wheren> 1,nums, return an arrayoutputsuch thatoutput[i]is equal to the product of all the elements ofnumsexceptnums[i]. Solve it without division and in O(n). For example, given[1,2,3,4], return[24,12,8...
LeetCode Top 100 Liked Questions 238. Product of Array Except Self (Java版; Medium) 题目描述 Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4]...
Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. 给一个n个int的数组nums,其中n>1,返回一个数组,使得output[i]等于除了nums[i]之外所有nums元素的乘积 Example: 例子 Input: [1,...
代码: class Solution(object): def productExceptSelf(self, nums): n = len(nums) res = [1] * n temp = 1 for i in range(0, n - 1): res[i + 1] = res[i] * nums[i] for i in range(n - 1, 0, -1): res[i] *= temp ...
public int[] productExceptSelf(int[] nums) { int mul = 1; int zeroNums = 0; int zeroFirst = -1; for (int i = 0; i < nums.length; i++) { if (nums[i] == 0) { zeroNums++; if (zeroNums == 1) { zeroFirst = i; } continue; } mul *= nums[i]; } int[] res =...
https://leetcode.com/problems/product-of-array-except-self/ 分析: 假如可以利用除法,则利用(A[0]*A[1]*...A[n-1])/A[i],但一定要注意A[i]等于 0 的情况!!! 暴力解决需要使用O(n^2)来构建数组B,不够高效。 使用O(n)的时间复杂度来解决本题: ...
238. Product of Array Except Self Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6]...
238. Product of Array Except Self 0 / 0 / 创建于 5年前 / 思路 /* The given conditions restrict serveral approach to the problem. First one disables us to calculate a product of all the numbers and divide it by each number itself. The second one disables us to have a brute force ...
[LeetCode]238.Product of Array Except Self 题目 Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n)....