but they are competent: consultants can solve any problem in a single month. Each consultant demands two payments: one in advance (1 ≤payment≤M) to be paid at the start of the month problem-solving is commenced and one more payment at the start of the month after...
POJ3265 Problem Solving ——动态规划——Pku3265 比较巧妙的动态规划。用f[i][j]表示第i个月,总工作了j道题目(从1~j),所能剩余的最多钱数。 状态转移方程如下: f[i][j]=Max(m-∑b[j]-∑b[k]){其中,k应当满足f[i-1][k]>=∑a[j]-∑a[k]} 注意最后输出的应该是ans+1,因为第一个月实...
poj 3265 Problem Solving dp 这个题目容易让人误以为是贪心就可以解决了,但是细想一下很容易举出反例。 dp[i][j]表示解决了i个问题,最后一个月解决的问题数目。 #include <iostream> #include <cstdio> #include <cstring> using namespace std; const int maxn=3e2+9; int a[maxn],b[maxn]; int s...