D. Stamp Stamp Stamp time limit per test1.5 seconds memory limit per test512 megabytes Cat Noku has a strip of paper that consists of n blank cells lying side by side. He has a painting s he wants to paint. This means, he would like to paint it so that the the i-th cell will ...
D. Integers Have Friends time limit per test 2 seconds memory limit per test 256 megabytes British mathematician John Littlewood once said about Indian mathematician Srinivasa Ramanujan that "every positive integer was one of his personal friends." ...
#include <cstdio>#include<algorithm>usingnamespacestd;constintmaxn = 2e5+5;intcur[maxn];intpre[maxn];intFind(intx) {returnpre[x] == x ?x : Find(pre[x]);}intmain() {intn; scanf("%d",&n);intthread =0;intans =0;for(inti =1; i<=n; i++) pre[i] =i;for(inti =1;...
Problem - D - Codeforces Example input 5 4 1 2 -1 2 3 1 1 -2 5 2 0 -2 2 -1 3 -2 -1 -1 3 -1 -2 -2 output 0 2 3 0 2 0 0 1 1 0 最近赛中敲不出代码, 赛后倒是镇静了, 我也醉了 简
题目链接:http://codeforces.com/contest/761/problem/D 题意:有一个序列c由序列a和b构造,c[i] = b[i]-a[i],现告诉你a和b中的元素范围都在l和r内,现告诉你a这个序列的元素,在告诉你c这个序列的排名即p[i]代表c[i]在c中为第几小,问你能否构造出一个b序列来 ...
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CodeForces - 1000D D. Yet Another Problem On a Subsequence 好题,D.YetAnotherProblemOnaSubsequencetimelimitpertest2second
以竖切的左半边为例,预处理出左半边每个点向上&向下同色能扩展多长,以及mid上的每个点向左同色能扩展多长len[i]。枚举d=j-i和i,那对于每一对i,j如果len[i]比len[j]长答案就是j上面向上扩展>=j-i的个数,否则就是i上向下扩展能>=j-i的个数。那我们让j-i单调增,给能扩展的长度分别桶排一下(直接...
Codeforces 1000D Yet Another Problem On a Subsequence 【dp】【组合数学】 2018-06-30 20:47 − ... 4397 0 508 相关推荐 Codeforces Round #598 (Div. 3) E - Yet Another Division Into Teams (dp) 2019-12-11 21:14 − 传送门 AC代码 /* 先排序,因为取连续的一段数作为一队,diff肯定是...
x),p.y+r/d*(cr.y-p.y),r); } int sgn(dd a){ return (a>eps)-(a<-eps); } bool sameside(cir a,cir b,cir s,cir t){ return sgn(xmult(s,t,a))==sgn(xmult(s,t,b));//利用叉积判断是否在直线同侧 } void tangent(cir a,cir b){ cnt=0; dd base=atan2(b.y-a.y,...