Re: printf for a char in hex - why all the F's? scrodchunk wrote:[color=blue] > I'm having a weird problem with printing bytes in hex format. > > I have a bunch of print statements that are working okay, then using > the identical formatting later in my code I get some thing...
#endifset_TR3; //Trigger Timer3TI_1 = 1;//For printf function must setting TI = 1}【3】UART1 prinf重定向函数char putchar (char c)//for UART1_printf{while (!TI_1);//wait until transmitter readyTI_1 = 0;SBUF_1 = c;//output characterreturn (c);}【4】...
#include <stdio.h> #include <stdlib.h> int main(void) { char ch = 'h', *string = "computer"; int count = 234, hex = 0x10, oct = 010, dec = 10; double fp = 251.7366; wchar_t wc = (wchar_t)0x0058; wchar_t ws[4]; printf("1234567890123%n4567890123456789\n\n", &count...
1#ifndef __PRINT_H_2#define__PRINT_H_34voidprint(char*fmt, ...);5voidprintch(charch);6voidprintdec(intdec);7voidprintflt(doubleflt);8voidprintbin(intbin);9voidprinthex(inthex);10voidprintstr(char*str);1112#defineconsole_print(ch) putchar(ch)1314#endif/*#ifndef __PRINT_H_*/ ...
char destination[256]; int a = 123; sprintf(destination, "number is decimal %d hex %x", a, a); #2 0 I did not recollect any library function. 我没有回忆任何库函数。 But the traditional mathematical way is below. I you want you can create a user defined function. ...
char destination[256]; int a = 123; sprintf(destination, "number is decimal %d hex %x", a, a); #2 0 I did not recollect any library function. 我没有回忆任何库函数。 But the traditional mathematical way is below. I you want you can create a user defined function. ...
char ch = 'h', *string = "computer";int count = -9234;double fp = 251.7366;wchar_t wch = L'w', *wstring = L"Unicode";/* Display integers. */ printf( "Integer formats:\n""\tDecimal: %d Justified: %.6d Unsigned: %u\n",count, count, count, count );pr...
#include <stdio.h> int main( void ) { char ch = 'h', *string = "computer"; wchar_t wch = L'w', *wstring = L"Unicode"; int count = -9234; double fp = 251.7366; // Display integers printf( "Integer formats:\n" " Decimal: %d Justified: %.6d " "Unsigned: %u\n", count...
#include <stdio.h> #include <stdlib.h> int main(void) { char ch = 'h', *string = "computer"; int count = 234, hex = 0x10, oct = 010, dec = 10; double fp = 251.7366; wchar_t wc = (wchar_t)0x0058; wchar_t ws[4]; printf("1234567890123%n4567890123456789\n\n", &count...
return pBin; } // 十进制转换为十六进制,十进制数的每4bit转换为十六进制的1位数字 char* tenToHex(unsigned int data) { int bitNum =sizeof(int)*8; char *pHex = new char[sizeof(int)*8/4+3]; pHex[0]='0'; pHex[1]='x';