Approach 1: Using Recursion The problem is very similar to the 0/1 knapsack problem, where for each element in set S, we have two options: Consider that element. Don’t consider that element. The following solution generates all combinations of subsets using the above logic. To print only ...
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C++ implementation of Print bracket number #include <bits/stdc++.h>usingnamespacestd;voidprint(vector<int>a) {for(inti=0; i<a.size(); i++) cout<<a[i]<<" "; cout<<endl; }voidmy(string s) { stack<int>st; vector<int>a;intcount=1;for(inti=0; i<s.length(); i++) {if(...